False .........................................
Answer:
I think its this 4.125 g Na2SO4 or this 4.125 g
Answer:
because of the substance contained in a fire extingudher it woulfnt start a fire.
Answer:
Ca3(PO4)2 + 3H2SO4 —> 3CaSO4 + 2H3PO4
The coefficients are 1, 3, 3, 2
Explanation:
Ca3(PO4)2 + H2SO4 —> CaSO4 + H3PO4
From the above equation,
There are 3 atoms of Ca on the left and 1 atom of Ca on the right. To balance Ca, put 3 in front of CaSO4 as shown below
Ca3(PO4)2 + H2SO4 —> 3CaSO4 + H3PO4
Now, we have 3 atoms of SO4 on the right and 1atom on the left. To balance SO4, put 3 in front of H2SO4 as shown below:
Ca3(PO4)2 + 3H2SO4 —> 3CaSO4 + H3PO4
Looking closely, there are 6 atoms of H on the left and 3 on the right. Therefore, it is balanced by by putting 2 in front of H3PO4 as shown below:
Ca3(PO4)2 + 3H2SO4 —> 3CaSO4 + 2H3PO4
The coefficients are 1, 3, 3, 2
<u>Answer:</u> The mass of manganese(III) oxide produced is 113.03 g
<u>Explanation:</u>
The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:
......(1)
Given mass of zinc = 46.8 g
Molar mass of zinc = 65.38 g/mol
Plugging values in equation 1:
The given chemical equation follows:
By the stoichiometry of the reaction:
If 1 mole of zinc produces 1 mole of manganese(III) oxide
So, 0.716 moles of zinc will produce = of manganese(III) oxide
Molar mass of manganese(III) oxide = 157.87 g/mol
Plugging values in equation 1:
Hence, the mass of manganese(III) oxide produced is 113.03 g