All categories

3 years ago

Caz(PO4)2 + H2504 - CaSO4+H3PO4

Chemistry

1 answer:

m_a_m_a [10]3 years ago

7 0

Answer:

Ca3(PO4)2 + 3H2SO4 —> 3CaSO4 + 2H3PO4

The coefficients are 1, 3, 3, 2

Explanation:

Ca3(PO4)2 + H2SO4 —> CaSO4 + H3PO4

From the above equation,

There are 3 atoms of Ca on the left and 1 atom of Ca on the right. To balance Ca, put 3 in front of CaSO4 as shown below

Ca3(PO4)2 + H2SO4 —> 3CaSO4 + H3PO4

Now, we have 3 atoms of SO4 on the right and 1atom on the left. To balance SO4, put 3 in front of H2SO4 as shown below:

Ca3(PO4)2 + 3H2SO4 —> 3CaSO4 + H3PO4

Looking closely, there are 6 atoms of H on the left and 3 on the right. Therefore, it is balanced by by putting 2 in front of H3PO4 as shown below:

Ca3(PO4)2 + 3H2SO4 —> 3CaSO4 + 2H3PO4

The coefficients are 1, 3, 3, 2

You might be interested in

Consider the following reaction where Kc = 154 at 298 K.2NO(g) + Br2(g) 2NOBr(g)A reaction mixture was found to contain 4.64×10-

IgorLugansk [536]

Answer:

The reaction is not at equilibrium and reaction must run in forward direction.

Explanation:

At the given interval, concentration of NO = $\frac{4.64\times 10^{-2}}{1}M=4.64\times 10^{-2}M$

Concentration of $Br_{2}$ = $\frac{4.56\times 10^{-2}}{1}M=4.56\times 10^{-2}M$

Concentration of NOBr = $\frac{0.102}{1}M=0.102M$

Reaction quotient, $Q_{c}$ , for this reaction = $\frac{[NOBr]^{2}}{[NO]^{2}[Br_{2}]}$

species inside third bracket represents concentrations at the given interval.

So, $Q_{c}=\frac{(0.102)^{2}}{(4.64\times 10^{-2})^{2}\times (4.56\times 10^{-2})}=106$

So, the reaction is not at equilibrium.

As $Q_{c}< K_{c}$ therefore reaction must run in forward direction to increase $Q_{c}$ and make it equal to $K_{c}$ .

4 0

2 years ago

How many ligaments in e kne

Makovka662 [10]

4.
Medial collateral ligament, which runs along inside of the knee.
Lateral collateral ligament, which runs along the outside of the knee.
Ligament, which runs in the middle part of the knee.
Posterior cruciate ligament, which works together with the Anterior cruciate ligament.

7 0

2 years ago

How many moles are in 2.5L of 1.75 M Na2CO3

Natasha_Volkova [10]

Answer:

4.4 mol.

Explanation:

Hello!

In this case, since the formula for calculating the molarity is:

$M=n/V$