Answer:
- Volume of the solution will increase.
- Molarity will decrease.
Explanation:
Hello,
In this case, for molarity, unit of concentration relating the moles of solute and volume of solution, we have:
Hence, since the given molarity is 0.70M, we first shall infer that by adding more water, that for sure is the solvent, the volume of the solution will increase which will be the first change. Moreover, since the volume and the molarity are in an inversely proportional relationship, as the volume increases the molarity decreases, which is the other change. In addition to the aforementioned statements, the moles of the solute are not modified as just water is added.
Best regards.
C2H4(g) + 2O2(g) → 2CO(g) + 2H2O(g) ∆H1 = −758 kJ mol−1 ....1)
2C(s) + 2H2(g) → C2H4(g) ∆H2 = +52 kJ mol−1 ....2)
H2(g) + O2(g) → H2O(g) ∆H3 = −242 kJ mol−1 ....3)
Now, enthalpy of formation of carbon monoxide is given by :
∆H = ∆H1 + ∆H2 - ∆H3
∆H = ( -758 + 52 - ( -242 ) ) kJ mol−1
∆H = −464 kJ mol−1
Therefore, the enthalpy of formation of carbon monoxide is -464 kJ mol−1.
Hence, this is the required solution.
There are two kinds of bonds in organic chemistry, sigma bonds and pi bonds. Sigma bonds are formed by end to end or head to head overlap of atomic orbitals.
Pi bonds are formed by side by side overlap of atomic orbitals.
In the compound 4-methyl-pent-2-ene, there are 15 sigma bonds and only one pi bond.
Hence, in the compound 4-methyl-pent-2-ene, there are 15 sigma bonds.
<em>Refer to the attachment </em><em>!</em><em>!</em><em>!</em>