Question

Write the equilibrium constant expression, K, for the following reaction. Please enter the compounds in the order given in the reaction. If either the numerator or denominator is blank, please enter 1
(aq) H2O(l) H3O (aq) (aq)

Answer 1

This question is an incomplete question, here is a complete question.

Write the equilibrium constant expression, K, for the following reaction. Please enter the compounds in the order given in the reaction. If either the numerator or denominator is blank, please enter 1

$HNO_2(aq)+H_2O(l)\rightleftharpoons H_3O^+(aq)+NO_2(aq)$

Answer : The correct expression for equilibrium constant will be, $K=[tex]K=\frac{[H_3O^+][NO_2]}{[HNO_2]}$

Explanation :

Equilibrium constant : It is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.

The equilibrium expression for the reaction is determined by multiplying the concentrations of products and divided by the concentrations of the reactants and each concentration is raised to the power that is equal to the coefficient in the balanced reaction.

As we know that the concentrations of pure solids and liquids are constant that is they do not change. Thus, they are not included in the equilibrium expression.

The given equilibrium reaction is,

$HNO_2(aq)+H_2O(l)\rightleftharpoons H_3O^+(aq)+NO_2(aq)$

The expression of $K$ will be,

$K=\frac{[H_3O^+][NO_2]}{[HNO_2]}$

Therefore, the correct expression for equilibrium constant will be, $K=\frac{[H_3O^+][NO_2]}{[HNO_2]}$