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Mariulka [41]
3 years ago
12

According to ohm's law what is the resistance of a light bulb if the applied voltage is 21 volts and the current is 3 amps?

Physics
1 answer:
Nady [450]3 years ago
6 0
Resistance = voltage/current = 21/3 = 7Ω
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lys-0071 [83]

Maybe this will help you out:

Momentum is calculate by the formula:

P = mv

Where:

P = momentum

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v = velocity

The SI unit:

mass = kg\\ velocity = \dfrac{m}{s}

So the unit of momentum would be:

kg.\dfrac{m}{s}

Impulse is defined as the change in momentum or how much force changes momentum. It can be calculate with the formula:

I = FΔt

where:

I = impulse

F = Force

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The SI unit:

F = Newtons (N) or kg.\dfrac{m}{s^{2} }

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So the unit of impulse would be derived this way:

I = FΔt

I = kg.\dfrac{m}{s^{2} } x s

or

\dfrac{kg.m.s}{s^{2}} = \dfrac{kg.m.s}{s.s}

You can then cancel out one s each from the numerator and denominator and you'll be left with:

kg.\dfrac{m}{s}

So then:

Momentum:                             Impulse

kg.\dfrac{m}{s}                                       kg.\dfrac{m}{s}

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Answer:

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Explanation:

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Answer:

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Explanation:

From the question we are told that

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3 years ago
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