The plane is not accelerating.
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The study of science involves the study of the natural world.
Answer:
a) P1=100kpa
V1=6m³
V2=?
P2=50kpa
rearranging mathematically the expression for Boyle's law
V2=(P1V1)/P2=(100×6)/50=12m³
b) same apartment as in (a) but only the value of P2 changes
=> V2=(100×6)/40=15m³
Explanation:
since temperature is not changing we use Boyle's law. mathematically expressed as P1V1=P2V2
Answer:
the horizontal distance covered by the cannonball before it hits the ground is 327.5 m
Explanation:
Given;
height of the cliff, h = 210 m
initial horizontal velocity of the cannonball, Ux = 50 m/s
initial vertical velocity of the cannonball, Uy = 0
The time for the cannonball to reach the ground is calculated as;
The horizontal distance covered by the cannonball before it hits the ground is calculated as;

Therefore, the horizontal distance covered by the cannonball before it hits the ground is 327.5 m
Answer:
period of oscillations is 0.695 second
Explanation:
given data
mass m = 0.350 kg
spring stretches x = 12 cm = 0.12 m
to find out
period of oscillations
solution
we know here that force
force = k × x .........1
so force = mg = 0.35 (9.8) = 3.43 N
3.43 = k × 0.12
k = 28.58 N/m
so period of oscillations is
period of oscillations = 2π ×
................2
put here value
period of oscillations = 2π ×
period of oscillations = 0.6953
so period of oscillations is 0.695 second