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Vladimir [108]
3 years ago
6

Please help asap, thank youuu

Mathematics
1 answer:
sveticcg [70]3 years ago
3 0

Hence the correct final answer is:

\frac{4y^3}{x^3}

Further explanation:

Given

Line\ 1: \frac{4}{1}.\frac{x^{-2}}{1}.\frac{1}{x}.\frac{y}{1}.\frac{1}{y^{-2}}

The student made the mistake in line two. There was no need to move 4 in the first term, from numerator to denominator

The correct line 2 will be:

Line\ 2: \frac{4}{1}.\frac{1}{x^2}.\frac{1}{x}.\frac{y}{1}.\frac{y^{2}}{1}}\\Line\ 3: \frac{4y^3}{x^3}

Hence the correct final answer is:

\frac{4y^3}{x^3}

Keywords: Fractions, exponents

Learn more about exponents at:

  • brainly.com/question/5014716
  • brainly.com/question/5147732

#learnwithBrainly

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