The complete version of question:
<em>Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26. What is the solution of this problem.</em>
Answer:
Step-by-step explanation:
As the description of the statement is:
'<em>Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26'.</em>
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As
- <em>Five times the sum of a number and 27 </em>is written as:

- <em>greater than or equal </em>is written as:

- <em>six times the sum of that number and 26' </em>is written as: 6(x + 26)
so lets combine the whole statement:
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solving
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Therefore,
She bought 2 1/4 more blue ribbon.
4 3/8 - 2 1/8 = 2.25
2.25= 9/4
9/4= 2 1/4
-Katie ;)
12=2.55 how about 8
8 x 2.55 divided by 12=$1.7
Answer:
A. The reflection preserves the side lengths and angles of triangle . The dilation preserves angles but not side lengths.
Step-by-step explanation:
Reflection is a rigid transformation. It preserves both angles and side lengths. Dilation preserves angles, but changes all lengths by the same scale factor.
<h3>Application</h3>
The described triangle was subject to reflection, which preserves angles and lengths. It was also subject to dilation, which preserves angles, but not lengths.
The appropriate description is that of choice A.
Answer:
t = 3 arc cos(h/7)/π
Step-by-step explanation:
The equation h=7cos(pi/3 t) models the (h) height in centimeters after (t) seconds of a weight attached to the end of a spring that has been stretched and released. To solve the equation for t we will solve the equation step by step:
h=7cos(pi/3 t)
Step 1)
Divide both sides by 7
h/7 = 7cos(pi/3 t)/7
Now the equation becomes h/7=cos(pi/3 t)
Step 2)
h/7=cos(pi/3 t)
Now apply inverse cosine function:
arc cos (h/7) = pi/3 t
Step 3)
t = 3 arc cos(h/7)/pi
Thus t = 3 arc cos(h/7)/pi ....