Answer:
D. 
Explanation:
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In this case, for the given set of chemical reactions, it is possible to infer that D. is a categorized as redox due to the following:
Since both chlorine and bromine remain as diatomic gases, their oxidation states in such a form is 0, but as anions with lithium cations they have a charge of - according to the following reaction and half-reactions:


Unlike the other reactions whereas no change in the oxidation states is evidenced.
Answer:
• Molecular mass of Iron (III) tetraoxide

[ molar masses: Fe → 56, O → 16 ]

Explanation:
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The Answer is 10 it a little difficult to explain but I’ll try my best