Answer:
NBr₃ is the excess reactant.
Explanation:
- 2NBr₃ + 3NaOH → N₂ + 3NaBr + 3HOBr
We can solve this problem by <u>calculating how many moles of NaOH would react completely with 40 moles of NBr₃</u>, using the <em>stoichiometric coefficients </em>of the reaction:
- 40 mol NBr₃ *
=60 moles NaOH
As the required number of NaOH moles is higher than the available number (60 required vs 48 available), NaOH is the limiting reactant.
As such, the excess reactant is NBr₃.
Answer:
Thus there was no accumulation of ions on the nails, as the dissolved gases were already removed, hence no rust formation. In test tube C, a chemical was added to absorb the water vapour. We know that rust formation takes place when a metal is exposed to water vapour.
Explanation:i hope u have a wonderful night and stays safe
false all element when they are combined eachother thier valance number will change
the combination of oxygen and aluminum gives us Al2O3 see even the numbers are changing thank you if you have a comment you can write
Answer: C
Explanation:
Answer is "It does not change"
Hope this helps!
The density of the liquid is 1.027g/cm³
D=M/V
D=46.83/45.6
D=1.027g/cm³
