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valentinak56 [21]
3 years ago
14

KOH +HBr KBr+ H2O Which is the acid in this reaction?

Chemistry
2 answers:
Allisa [31]3 years ago
5 0

Answer:

HBr Potassium bromide

liq [111]3 years ago
3 0
HBr is the acid in the reaction
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How is the number of electrons in an element determined?
elixir [45]

The number of protons, neutrons, and electrons in an atom can be determined from a set of simple rules. The number of protons in the nucleus of the atom is equal to the atomic number (Z). The number of electrons in a neutral atom is equal to the number of protons.

3 0
2 years ago
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The total number of atoms in the formula aluminum acetate is
REY [17]

Answer:

B) 22 atoms

Explanation:

Aluminum Acetate has a formula of C6H9AlO6, meaning that it has 6 Carbon atoms, 9 Hydrogen atoms, 1 Aluminum atom, and 6 Oxygen atoms.

In total there are: 6+9+1+6 atoms, or a total of 22 atoms.

Hope this helps!

7 0
3 years ago
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How many moles of C2H2 are needed to react completely with 84 mol O2
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Balanced chemical equation:

2 C2H2 + 5 O2 = 4 CO2 + 2 H2O

2 moles C2H2 ---------------- 5 moles O2
moles C2H2 ------------------ 84 moles O2

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4 0
3 years ago
Identify the oxidizing agent and the reducing agent for 4Li(s) + O_2 (g) to 2Li_2O(s).
wolverine [178]

Answer: Li is the reducing agentg and O is the oxidizing agent.

Explanation:

1) The oxidizing agent is the one that is reduced and the reducing agent is the one that is oxidized.

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3) Determine the oxidation states of each atom:

Li(s): oxidation state = 0 (since it is alone)

O₂ (g): oxidation state = 0 (since it is alone)

Li in Li₂O (s) +1

O in Li₂O -2

That because 2× (+1) - 2 = 0.

4) Determine the changes:

Li went from 0 to + 1, therefore it got oxidized and it is the reducing agent.

O went from 0 to - 2, therefore it got reduced and it is the oxidizing agent.

7 0
3 years ago
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C-12, c-13, and c-14 have the same number of protons but different numbers of neutrons so they are
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Atoms with the same number of protons, but different numbers of neutrons are isotopes of the same element.
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