All categories

3 years ago

Alcohol __________ by making it difficult to anticipate driving situations.

Chemistry

2 answers:

svlad2 [7]3 years ago

8 0

Makes driving less stressful

Gnom [1K]3 years ago

6 0

Answer:

makes driving less stressful

Explanation:

When a person consume alcohol, it affects the brain of the person.

The effect of alcohol is that it makes the person more relaxed and thus the person is not able to anticipate the dangers associated with any obstacle or other vehicle and thus may cause accident.

It is true that the person reaction time or reflex time also increases due to consumption of alcohol.

You might be interested in

If two substances travel up the chromatography paper this implies that

Colt1911 [192]

Answer:

They are seperating

Explanation:

6 0

2 years ago

4) What volume will the gas in the balloon at right occupy at 250k?<br><br> balloon: 4.3L 350K

swat32

Answer:

2.87 liter.

Explanation:

Given:

Initially volume of balloon = 4.3 liter

Initially temperature of balloon = 350 K

Question asked:

What volume will the gas in the balloon occupy at 250 K ?

Solution:

By using:

$Pv =nRT$

Assuming pressure as constant,

V∝ T

Now, let K is the constant.

V = KT

Let initial volume of balloon , $V_{1}$ = 4.3 liter

1000 liter = 1 meter cube

1 liter = $\frac{1}{1000} m^{3} = 10^{-3} m^{3$

4.3 liter = $4.3\times10^{-3}=4.3\times10^{-3} m^{3}$

And initial temperature of balloon, $T_{1}$ = 350 K

Let the final volume of balloon is $V_{2}$

And as given, final temperature of balloon, $T_{2}$ is 250 K

Now, $V_{1} = KT_{1}$

$4.3\times10^{-3}=K\times350\ (equation\ 1 )$

$V_{2} = KT_{2}$

$=K\times250\ (equation 2)$

Dividing equation 1 and 2,

$\frac{4.3\times10^{-3}}{V_{2} } =\frac{K\times350}{K\times250}$

K cancelled by K.

By cross multiplication:

$350V_{2} =4.3\times10^{-3} \times250\\V_{2} =\frac{ 4.3\times10^{-3} \times250\\}{350} \\ = \frac{1075\times10^{-3}}{350} \\ =2.87\times10^{-3}m^{3}$

Now, convert it into liter with the help of calculation done above,

$2.87\times10^{-3} \times1000\\2.87\times10^{-3} \times10^{3} \\2.87\ liter$

Therefore, volume of the gas in the balloon at 250 K will be 2.87 liter.

4 0

3 years ago

if a baloon filled with dry hydrogen weighs 35 gram,but weighs 440 grams when filled with the vapour of an organic compound. cal

Elan Coil [88]

Answer:

1) The vapor density of the organic compound is approximately 12.57

2) The relative molar mass (RMM) of the organic compound is approximately 25.14 grams

Explanation:

1) The mass of the balloon filled with dry hydrogen = 35 grams

The mass of the balloon filled with vapor of an organic compound = 440 grams

The vapor density = (Weight of a given volume of gas)/(Weight of equal volume of hydrogen)

The vapor density of the organic compound = (440)/(35) ≈ 12.57

The vapor density of the organic compound ≈ 12.57

2) The relative molar mass (RMM) = 2 × vapor density

The relative molar mass (RMM) of the organic compound = 2 × vapor density of the organic compound

The relative molar mass (RMM) of the organic compound ≈ 2 × 12.57 ≈ 25.14 grams

The relative molar mass (RMM) of the organic compound ≈ 25.14 grams

6 0

2 years ago

The heating element of a hair dryer dissipates 1500 w when connected to a 180 v outlet. part a what is its resistance?

Sophie [7]

The resistance of the heating element is 21.61 Ω

Given

The power dissipated = 1500 W

Voltage = 180 V

We know that

Power = Voltage * Current

⇒ Power / Voltage = Current

⇒ 1500 W/180 V = Current

⇒ 8.33 A = Current

In order to calculate the resistance of the heating element. We Have to apply the formula

Power = (Current)^2 * Resistance

⇒ Resistance = Power / (Current)^2

⇒ Resistance = 1500 W/ (8.33) ^2

⇒ Resistance = 21.61 Ω

Hence the resistance of the heating element is 21.61 Ω

Learn more about resistance here: -

“ brainly.com/question/17330679 “

#SPJ4

5 0

1 year ago

For many purposes we can treat propane

dangina [55]

Answer:The volume increases by 11%

Explanation:

When the pressure is decreased, the volume must definitely increase, to maintain the same pressure, the temperature must then also be increased as we see in the question. The volume was increased just as the pressure decreased and the temperature had to be increased to maintain a constant pressure. We have applied the general gas equation in solving the problem.

3 0

3 years ago