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3 years ago

What are the pros and cons of using Nitrous Oxide in a vehicle?

Chemistry

1 answer:

coldgirl [10]3 years ago

3 0

Hello!

Some benefits of using nitrous oxide in a vehicle are as follows:

* N2O produces a larger combustion and thus fuels the car for longer periods of time.

* N2O is comparatively inexpensive for what its worth.

* N2O, under certain circumstances, is safer than other alternative sources of fuel because it's not flammable.

Some disadvantages of using nitrous oxide in a vehicle are as follows:

* Since N2O is a gas, it takes up a lot of empty space and can't be stored in large amounts.

* It can occasionally blow up, even though it almost never does.

I hope I helped! :-)

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Chemosynthesis and photosynthesis are both processes that produce food. True or false?

MA_775_DIABLO [31]

Answer:

true

Explanation:

probably true

8 0

3 years ago

When scientists are ready to publish the results of their experiments, why is it important for them to include a description of

gizmo_the_mogwai [7]

Answer: To be able to not forget what have they done when they want to re-do it.

to make it easier for the next person to re-do the experiment.

Explanation:

the description of the procedure ensures that when the experiment becomes of a success,specific steps are recorded for improvement of the experiment if maybe the experiment can be done at a short space of time.

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3 years ago

In the gas-phase reaction 2 A + B ⇌ 3 C + 2 D, it was found that, when 1.00 mol A, 2.00 mol B, and 1.00 mol D were mixed and all

Naddik [55]

Answer:

(i)The mole fractions are :

$A=\frac{0.4}{4.3} \\=0.0930$

$B=\frac{1.4}{4.3} \\=0.3256$

$C=\frac{0.9}{4.3} \\=0.2093$

$D=\frac{1.6}{4.3} \\=0.3721$

(ii) $K=0.4508$

(iii)ΔG = 1.974kJ

Explanation:

The given equation is :

$2A+B$ ⇄ $3C+2D$

Let $\alpha$ be the number of moles dissociated per mole of $B$

Thus ,

The initial number of moles of :

$A=1$

$B=2$

$C=0$

$D=1$

$2A\\(1-2\alpha)$ + $B\\2(1-\alpha)$ ⇄ $3C\\(3\alpha)$ + $2D\\(1+2\alpha)$

And finally the number of moles of $C[tex] is 0.9Thus ,[tex]3\alpha=0.9\\\alpha=0.3[tex]The final number of moles of:[tex]A = 1-2\alpha=1-2*0.3=0.4mol[tex] [tex]B=2(1-\alpha)=2(1-0.3)=1.4mol[tex][tex]D=1+2\alpha=1+2*0.3=1.6mol[tex]Thus , total number of moles are : 0.4+1.4+0.9+1.6=4.3(i)The mole fractions are : [tex]A=\frac{0.4}{4.3} \\=0.0930$

$B=\frac{1.4}{4.3} \\=0.3256$

$C=\frac{0.9}{4.3} \\=0.2093$

$D=\frac{1.6}{4.3} \\=0.3721$

(ii)

$K=\frac{(P_C^3)(P_D^2)}{(P_A^2)(P_B)}$

Where ,

$P_A,P_B,P_C,P_D$ are the partial pressures of A,B,C,D respectively.

Total pressure = 1 bar .

∴

$P_A= 0.0930*1=0.0930$

$P_B= 0.3256*1=0.3256$

$P_C= 0.2093*1=0.2093$

$P_D= 0.3721*1=0.3721$

$K=\frac{0.2093^3*0.3721^2}{0.0930^2*0.3256} \\K=0.4508$

(iii)

Δ $G=-RTlnK\\$

ΔG = $-8.314*(273+25)*ln(0.4508)\\=1973.96J\\=1.974kJ$

3 0

3 years ago

What is your calculated density of water at R.T.?

Alekssandra [29.7K]

The mass of 40 mL of water is 40 grams. Since D = m/v and mL = cm3, the density of water is 1 g/cm3. Choose a volume between 1 and 100 mL. Use your graph to find the mass.

3 0

3 years ago

(d) If you have 9.44 g of NazPO4, how many grams of AgNO, will be needed for complete

AlladinOne [14]

30.6 g of AgNO₃

Explanation:

We have the following chemical reaction:

Na₃PO₄ + 3 AgNO₃ → Ag₃PO₄ + 3 NaNO₃

Now we calculate the number of moles of Na₃PO₄:

number of moles = mass / molecular weight

number of moles of Na₃PO₄ = 9.44 / 164 = 0.06 moles

Now we formulate the following reasoning:

if 1 mole of Na₃PO₄ will react with 3 moles of AgNO₃

then 0.06 moles of Na₃PO₄ will react with X moles of AgNO₃

X = (0.06 × 3) / 1 = 0.18 moles of AgNO₃

mass = number of moles × molecular weight

mass of AgNO₃ = 0.18 × 170 = 30.6 g

Learn more about:

mole concept

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#learnwithBrainly

3 0

3 years ago