Answer:
- The temperature of 10°C will be experienced at an altitude of 2.52 km
- The temperature of 0°C will be experienced at an altitude of 4.15 km
Explanation:
Lapse Rate = -6.5°C/km of ascent.
Lapse Rate = Temperature difference/altitude difference
For the 10°C,
Temperature difference = 10 - 27 = -17°C
-6.5 = -17/(difference in altitude between the two points)
Difference in altitude = 17/6.5 = 2.52 km
For 0°C,
Temperature difference = 0 - 27 = - 27°C
-6.5 = -27/(difference in altitude between the two points)
Altitude difference = 27/6.5 = 4.15 km
Answer: 1.59 sec
Explanation:
The kinetic energy contained in the rotation of the cylinder is 1/2 m v^2
The kinetic energy of translation is also 1/2 m v^2
so the total energy is m v^2
The force applied is mg sin (theta)
= m x 9.8 x 1/2
= 4.9 m
Now equate
F x d = m v^2
4.9 m x 3.1 = m v^2
v^2 = 4.9 x 3.1
v = sqrt(4.9 x 3.1) = 3.9 m/s
Acceleration.
V^2 = 2 a s
4.9 x 3.1 = 2 x a x 3.1
4.9 = 2 a
a = 2.45 m/s^2
Time
T = v/a
= 3.9/2.45
= 1.59 sec
Answer:
The location of helicopter is behind the packet.
Explanation:
As the packet also have same horizontal velocity as same as the helicopter, and also it has some vertical velocity as it hits the ground.
The horizontal velocity remains same as there is no force in the horizontal direction. The vertical velocity goes on increasing as acceleration due to gravity acts.
So, the helicopter is behind the packet.
