<h2>
Explanation:</h2>
<h3>B. Chloroplast</h3>
<em>In </em><em>photosynthesis</em><em> </em><em><u>chloroplast</u></em><em> </em><em>inside</em><em> the</em><em> </em><em>leaf </em><em>contain</em><em> </em><em>chlorophyll</em><em> </em><em>which</em><em> </em><em>captures</em><em> </em><em>light</em><em> </em><em>energy</em><em> </em><em>for</em><em> </em><em>photosynthesis.</em>
<em><u>hope</u></em><em><u> this</u></em><em><u> helps</u></em><em><u> you</u></em>
<em><u>have</u></em><em><u> a</u></em><em><u> good</u></em><em><u> </u></em><em><u>day.</u></em>
Answer:
The density is 
Explanation:
From the question we are told that
The weight in air is 
The weight in water is 
The weight in a unknown liquid is 
Now according to Archimedes principle the weight of the object in water is mathematically represented as

Where
is he mass of the water displaced
substituting value


Now according to Archimedes principle the weight of the object in unknown is mathematically represented as

Where
is he mass of the unknown liquid displaced
substituting value


dividing equation 2 by equation 1


=> 
Now since the volume of water and liquid displaced are the same then

This because

So if volume is constant
mass = constant * density
Where
is the density of the liquid
and
is the density of water which is a constant with a value 
So


Because it has a small hole and air is like water, an area of higher pressure wants to move to a lower pressure area.
Answer: 272.82 drop/tile
Explanation:
Given that the Rain drops fall on a tile surface at a density of 4638 drops/ft2. There are 17 tiles/ft2. How many drops fall on each tile?
Tiles/ft^2 × drop/tiles = drop/ft^2
Tiles will cancel out. Leaving the answer to be drop/ ft^2
Substitutes all the magnitude of the above units.
17 × drop/tiles = 4638
Make drop/tiles the subject of formula
Drop/tiles = 4638/17
Drop/tiles = 272.82
Therefore, 272.82 drop/tile drops fall on each tile?
Answer:
0.54m
Explanation:
Step one:
given data
length of seesaw= 3m
mass of man m1= 85kg
weight = mg
W1= 85*10= 850N
mass of daughter m2= 35kg
W2= 35*10= 350N
distance from the center= (1.5-0.2)= 1.3m
Step two:
we know that the sum of clockwise moment equals the anticlockwise moment
let the distance the must sit to balance the system be x
taking moment about the center of the system
350*1.3=850*x
455=850x
divide both sides by 850
x=455/850
x=0.54
Hence the man must sit 0.54m from the right to balance the system