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3 years ago

Calculate the frequency of the red light emitted by a neon sign with a wavelength of 690 nm

Physics

2 answers:

Ne4ueva [31]3 years ago

7 0

Answer:

$4.35 \times 10^{14} Hz$

Explanation:

The frequency of a light is inversely proportional to its wavelength. It is given by:

$f = \frac{v}{\lambda}$

The speed of the red light, v = 3.0 × 10⁸ m/s

The wavelength of the red light, λ = 690 nm = 690 ×10⁻⁹ m

$f = \frac{3.0 \times 10^8 m/s}{690\times 10^{-9}m} = 4.35 \times 10^{14} Hz$

Thus, the frequency of red light emitted by neon sign having wavelength 690 nm is $4.35 \times 10^{14} Hz$

son4ous [18]3 years ago

4 0

The frequency of red light emitted by neon sign having wavelength $690\text{ nm}$ is $\b{\boxed{4.35\times10^{14}\text{ Hz}}}$ .

Further Explanation:

Wavelength is defined as the distance between two successive highest points or it is the length traveled in one complete period for a periodic wave.

Frequency is defined as the number of waves passing through a point in a unit time and is inversely proportional to wavelength.

Red light is the part of visible light spectrum. It is electromagnetic in nature. It has a maximum wavelength and minimum frequency in a visible light spectrum and travels with the speed of $3\times10^8\text{ m/s}$ .

Neon emits mostly the red and green light but we can observe the visible spectrum in neon emission spectrum.

Given:

The wavelength of the red light is $690\text{ nm}$ .

Concept:

The relationship between wavelength and frequency given as:

$\boxed{f=\dfrac{v}{\lambda}}$

Substituting $3\times10^8\text{ m/s}$ for $v$ and $690&\times10^{-9}\text{ m}$ for $\lambda$ in above expression, we get

$f= 4.35\times10^{14}\text{ Hz}$

Thus, the frequency of red light emitted by neon sign having wavelength $690\text{ nm}$ is $\b{\boxed{4.35\times10^{14}\text{ Hz}}}$ .

Learn more:

1. Volume of gas after expansion: brainly.com/question/9979757

2. Principle of conservation of momentum: brainly.com/question/9484203

3. Average translational kinetic energy: brainly.com/question/9078768

Answer Details:

Grade: College

Subject: Physics

Chapter: Optics

Keywords:

Wavelength, successive, highest, complete, period, wave, frequency, unit, time, inversely, proportional, red, light, neon, maximum, minimum, visible, spectrum, 690nm, 3*10^8 m/s, speed, electromagnetic, nature and part.

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Corrected and Formatted Question:

A wave on a string is described by y(x, t) = (3.0 cm) × cos[2π(x/(2.4 m) + t/(0.20 s))], where x is in m and t in s.

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Answer:

The wave is travelling in the negative x direction

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The frequency = 5Hz

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Explanation:

The general wave equation is given by;

y(x, t) = y cos (2 $\pi$ (x/λ) - 2 $\pi$ ft) --------------------------------(i)

Where;

y(x, t) is the displacement of the wave at position x and a given time t

y = amplitude of the wave

f = frequency of the wave

λ = wavelength of the wave

Given;

y(x, t) = (3.0 cm) × cos[2π(x/(2.4 m) + t/(0.20 s))] ------------------(ii)

Which can be re-written as;

y(x, t) = (3.0 cm) × cos[2π(x/(2.4 m)) + 2π(t/(0.20 s))] -------------(iii)

Comparing equations (i) and (iii) we have that;

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Also, still comparing the two equations;

=> 2π(t/(0.20 s) = 2πft

=> f = 1 / 0.20

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Therefore the frequency of the wave is 5Hz

To get the wave speed (v), it is given by;

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=> v = 5 x 2.4

=> v = 12.0m/s

Therefore, the speed of the wave is 12.0m/s

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The displacement, y(x,t) of the string wave is given by

y(x, t) = (3.0 cm) × cos[2π(x/(2.4 m) + t/(0.20 s))]

Convert the amplitude of 3.0cm to m

=> 3.0cm = 0.03m

Substitute this back into the equation

=> y(x, t) = (0.03m) × cos[2π(x/(2.4 m) + t/(0.20 s))]

Substitute the values of t and x into the equation above;

=> y(x, t) = (0.03m) × cos[2π((0.20)/(2.4 m) + 0.50/(0.20 s))]

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=> y(x, t) = (0.03m) × cos[2π((0.20)/(2.4 m)) + 2π(0.50/(0.20 s))]

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=> y(x, t) = 0.029m

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