Answer:
The combination of oxygen with other substances to produce new chemical products is called <u>Oxidation</u>.
Explanation:
Oxidation reactions are defined as,
In terms of Inorganic chemistry:
(i) <u>Removal of Electrons: </u>
Example: Mg → Mg²⁺ + 2 e⁻
(ii) <u>Addition of Oxygen:</u>
Example: 2 Mg + O₂ → 2 MgO
In terms of Organic chemistry:
(i) <u>Addition of Electrons: </u>
Example: Cl₂ + 2 e⁻ → 2 Cl⁻
(ii) <u>Addition of Hydrogen:</u>
Example: H₂CCH₂ + H₂ → H₃CCH₃
Answer:
5.00 mol Mg
10.0 mol Cl
40.0 mol O
Explanation:
Step 1: Given data
Moles of Mg(ClO₄)₂: 5.00 mol
Step 2: Calculate the number of moles of Mg
The molar ratio of Mg(ClO₄)₂ to Mg is 1:1.
5.00 mol Mg(ClO₄)₂ × 1 mol Mg/1 mol Mg(ClO₄)₂ = 5.00 mol Mg
Step 3: Calculate the number of moles of Cl
The molar ratio of Mg(ClO₄)₂ to Cl is 1:2.
5.00 mol Mg(ClO₄)₂ × 2 mol Cl/1 mol Mg(ClO₄)₂ = 10.0 mol Cl
Step 4: Calculate the number of moles of O
The molar ratio of Mg(ClO₄)₂ to Cl is 1:8.
5.00 mol Mg(ClO₄)₂ × 8 mol O/1 mol Mg(ClO₄)₂ = 40.0 mol O
Answer:
The total number of orbitals for a given n value is n2.
Explanation:
For a hydrogen atom with n=1, the electron is in its ground state; if the electron is in the n=2 orbital, it is in an excited state.
