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3 years ago

Tengo que resolver con procedimiento

Chemistry

1 answer:

zzz [600]3 years ago

6 0

Answer:

Distance = 200 km

Distance = 204 km

Speed = 77 km/h

Time = 21.42 h

Explanation:

Given:

Speed = 100 km/h , Time = 2 h

Find:

Distance

Speed = 68 km/h , Time = 3 h

Find:

Distance

Distance = 154 km , Time = 2 h

Find:

Speed

Distance = 1500 km speed = 70 km/h

Find:

Time

Computation:

Speed = distance / time

Distance = 100 x 2

Distance = 200 km

Distance = 68 x 3

Distance = 204 km

Speed = 154 / 2

Speed = 77 km/h

Time = 1500 / 70

Time = 21.42 h

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True or false 12,785.000 has five significant digits.

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Complete Question

Questions Diagram is attached below

Answer:

* $W=1142.86Joule$

* $Q=997.7J$

* $H=2140.5J$

Explanation:

From the question we are told that:

Temperature $T=337K$

Pressure $P=(60-55)Pa*10^5$

Volume $V=(1.6-1.4)m^3*10^{-3}$

Generally the equation for gas Constant is mathematically given by

$\frac{P_2}{P_1}=\frac{V_1}{V_2}^n$

$\frac{55*10^5}{60*10^5}=\frac{1.4*10^{-3}}{1.6*10^{-3}}^n$

$n=0.65$

Therefore

Work-done

$W=\int{pdv}$

$W=\frac{55*10^5*1.6*10^{-3}*60*10^5*1.4*10^{-3}}{1-0.65}$

$W=1142.86Joule$

Generally the equation for internal energy is mathematically given by

$Q=mC_vdT\\\\Q=\frac{3*1*3.314*16}{1.4-1}$

$Q=997.7J$

Therefore

$H=Q+W$

$H=997.7J-11.42.9$

$H=2140.5J$

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2 years ago