The question is typed wrong. Assuming the correct question is
How many liters of 0.98 M H2SO4 solution would react completely with 3.5 moles Ca(OH)2 ?
Answer:-
3.571 litres
Explanation:-
The balanced chemical equation for this reaction is
H2SO4 + Ca(OH)2 = CaSO4 + 2 H2O
From the balanced chemical equation we see that
1 mole of Ca(OH)2 reacts with 1 mol of H2SO4.
∴3.5 moles of Ca(OH)2 reacts with 1 x 3.5 / 1 = 3.5 mol of H2SO4.
Strength of H2SO4 = 0.98 M
Volume of H2SO4 required = Number of moles of H2SO4 / Strength of H2SO4
= 3.5 moles / 0.98 M
= 3.571 litre
<span>H and Li have a +1 charge. Cl and OH have a -1 charge. When written out it should look like this:
H(+1) + Cl(-1) + Li(+1) + OH(-1) --> H2O + Li(+1) + Cl(-1)
if you wanted the net ionic equation it would be:
H(+1) + OH(-1) --> H2O</span>
The concentration of each of the individual ions in a 0750 M Ba(OH)2 solution is
[Ba2+] = 0.750 M
[OH-]= 1.50 M
<h3>
calculation</h3>
write the equation for dissociation
that is Ba(OH)2 (s)→ Ba2+(aq) + 2OH-(aq)
by use of mole ratio of Ba(OH)2 : Ba2+ which is 1: 1 the concentration of Ba2+ is therefore= 0.750M
by use of mole ratio of Ba(OH)2 : OH- which is 1:2 the concentration of OH- =0.750 M x2/1=1.50 M
Answer:
transitive physicsif something conducts heat or electricity, heat or electricity can move through it.
Explanation: