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AnnyKZ [126]
3 years ago
14

1. How is the atom count for each element on the reactant side of a balanced chemical equation related to the atom count for eac

h element on the product side of the same equation?
Chemistry
1 answer:
lbvjy [14]3 years ago
5 0

Answer: The atom count for each element on the reactant side of a balanced chemical equation is equal to the atom count for each element on the product side of the same equation

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products formed must be equal to the mass of reactants taken.

In order to get the same mass on both sides, the atoms of each element must be balanced on both sides of the chemical equation.

2H_2+O_2\rightarrow 2H_2O

Thus there are 4 atoms of hydrogen on reactant as well as product side.

Also there are 2 atoms of oxygen on reactant as well as product side.

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A ball is rolled at a velocity of 3 m/s and rolls for 5 seconds. How far does<br> the ball roll? *
MrRa [10]

Answer 15m

Explanation: Distance =  Speed x Time

3 x 5 =15

6 0
3 years ago
How many grams of hydrogen chloride can be produced from 1g of hydrogen and 55g of chlorine? What is the limiting reactant?
vova2212 [387]

Answer:

The limiting reactant is hydrogen, and the grams HCl produced is 36.175 g.

Explanation:

Balanced equation is 2 H + Cl2 = 2 HCl.

First thing, convert grams to moles via using molar mass.

Molar mass for hydrogen is 1.0079 g/mol. 1g x 1 mol / 1.0079 g = 0.99216 mol.

Molar mass for chlorine is 70.906 g/mol. 55g x 1 mol / 70.906 g = 0.7756748 mol.

Next, determine which is the limiting reactant - probably the fastest way to do it is just to take one of the reactants, say it's the limiting one, and calculate how much of the other reactant would be needed if that really was the limiting reactant, and then compare it to the actual moles of reactant available.

If hydrogen was the limiting reactant at 0.992 mol, you'd need .496 mol of Cl2 to complete the reaction.

If chloride was the limiting reactant at 0.776 mol, you'd need 1.55 mol of H to complete the reaction.

Comparing these numbers to the amounts we actually have available, the limiting reactant is hydrogen.

Once you've determined that, just plug in the amounts to the balanced equation to get the number of moles of HCL produced, which in this case, is just 0.992 mol.

Now, reverse the process that you took to get the moles of reactant, and you have the grams of product produced.

0.992 mol x 36.4609 g / 1 mol = 36.175 g.

7 0
3 years ago
natural selection is an example of a mechanism of evolution does this mechanism produce a change in individuals or populations e
skad [1K]

Answer: Yes, Natural selection is natures way of making the fittest and top dogs of the food chain, It can produce a change in individuals and populations by completely reducing or wiping out a population not fit for survival in its inviroment and can even force a change of the creature to make it able to survive.

Example: would be rabbits, a snow rabbit wouldn't survive very well in the desert and a jack rabbit wouldn't be able to survive in the cold winter due to temp and the fact that predators like wolves would be able to spot it easier from its color of its fur.

Note: Hope this helps, and I hope this is want it was asking. Good luck :)

8 0
3 years ago
What happens to the temperature and density of the material between points B and C?
makvit [3.9K]

Answer:

Temperature decreases and density increases

Explanation:

Let us remember that density of a material increases as the temperature of the material decreases. So the cooler a material becomes, the denser it becomes also.

Between points B and C, the material rapidly cools down and the temperature decreases accordingly. This ultimately results in an increase in density since cooler materials are denser than hot materials.

7 0
3 years ago
For the following pairs of ions, use the concept that a chemical compound must have a net charge of zero to predict the formula
Dafna11 [192]

\\ \sf\longmapsto FeP

\\ \sf\longmapsto Fe_2S_3

\\ \sf\longmapsto FeCl_2

\\ \sf\longmapsto MgCl_2

\\ \sf\longmapsto MgO

\\ \sf\longmapsto Mg_3N_2

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\\ \sf\longmapsto Co_2S_3

\\ \sf\longmapsto AlCl_3

\\ \sf\longmapsto CsBr

\\ \sf\longmapsto Ti_2O_4

\\ \sf\longmapsto Ag_2S

4 0
3 years ago
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