1. How is the atom count for each element on the reactant side of a balanced chemical equation related to the atom count for eac
1 answer:
Answer: The atom count for each element on the reactant side of a balanced chemical equation is equal to the atom count for each element on the product side of the same equation
Explanation:
According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products formed must be equal to the mass of reactants taken.
In order to get the same mass on both sides, the atoms of each element must be balanced on both sides of the chemical equation.
Thus there are 4 atoms of hydrogen on reactant as well as product side.
Also there are 2 atoms of oxygen on reactant as well as product side.
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The molar mass of the compound:
If the solution has an osmotic pressure of 8.44 torr, then the molar mass of the unknown non-electrolyte is 223.14 g.
What is osmosis?
- Osmosis is defined as the flow of solvent molecules through semi-permeable membrane.
- Osmotic pressure is the pressure applied to stop the flow of solvent molecules.
- It is a colligative property that means osmotic pressure depends on the number of solute particles .
Therefore,
π ( for electrolytes)
Where, π= Osmotic pressure
i = Van 't Hoff factor
n= moles
R= Gaseous constant = 62.363577 L torr
T= Temperature
V= Volume of solution
Given:
T= 298K
V= 150 mL= 0.150 L
Given mass of unknown electrolyte= 15.2 mg = 15.2 x g
Osmotic pressure= 8.44 torr
Molar mass= ?
For non-electrolytes:
πV = n RT
πV=RT
Calculations:
Putting the given values in the formula:
8.44 x 0.150 =15.2 x / M x 62.36 x 298
1.266 = 282.5/M
M = 282.5/1.266
M = 223.14 g
Therefore,
The molar mass of the unknown non-electrolyte is 223.14g.
Learn more about Osmotic pressure here,
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Answer : The volume of calcium hydroxide is, 32.89 ml
Explanation :
Using neutralization law,
where,
= basicity of an acid = 1
= acidity of a base = 2
= concentration of hydrobromic acid = 0.389 M
= concentration of calcium hydroxide = 0.0887 M
= volume of hydrobromic acid = 15 ml
= volume of calcium hydroxide = ?
Now put all the given values in the above law, we get the volume of calcium hydroxide.
Therefore, the volume of calcium hydroxide is, 32.89 ml