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drek231 [11]
3 years ago
9

0.580 repeating as a fraction

Mathematics
1 answer:
ElenaW [278]3 years ago
7 0

Answer:

Write out your decimal as the numerator of a fraction:

0.50 /1

Multiply to remove the 2 decimal places:

0.50 /1 ×  100 /100=  50 /100

Find the Greatest Common Factor of 50 and 100:

GCF is 50

Divide both numerator and denominator by 50:

50 ÷ 50

100 ÷ 50 =  1 /2

therefore your answer is 1/2

Hope this helps! (づ ̄3 ̄)づ╭❤~

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Allan is deriving the quadratic formula, as pictured below. His work is incorrect. In which step did Allan first make an error?
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Answer:

step 5 is the answer

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How many real numbers solutions does the equation have -8x^2-8x-2=0
Minchanka [31]
Using the attached formula, the only answer is
x =  -  \frac{1}{2}

3 0
4 years ago
a study of the effects of exercis used rats bred to have high or low capacity for exercise. The 8 high capacity rats had mean bl
zavuch27 [327]

Answer:

t=-2.86

Step-by-step explanation:

From the question we are told that:

Sample 1 n_1=8

Sample 1 mean blood pressure \=x_1=89mmHg

Sample 1 variance \sigma_1=81

Sample 2 n_2=8

Sample 2 mean blood pressure \=x_2=105mmHg

Sample 2 variance \sigma_2=169

Generally the equation for the test of statistic is mathematically given by

t=\frac{\=x_1-\=x_2}{\sqrt{\frac{\sigma_2}{n_1}+\frac{\sigma_2}{n_2} } }

t=\frac{89-105}{\sqrt{\frac{81}{8}+\frac{169}{8} } }

t=-2.86

therefore the samples test for comparing the two population means

t=-2.86

3 0
3 years ago
You are paid $11.75/hr. You work 40 hr/wk. Your deductions are FICA (7.65%), Federal tax withholding (10.75%), and state tax wit
marta [7]
Total income = 11.75 x 40 x 4 = $1,880
Less: FICA = 0.0765 x 1,880 = $143.82
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8 0
3 years ago
Read 2 more answers
Would appreciate the help ! ​
aleksandr82 [10.1K]

This is one pathway to prove the identity.

Part 1

\frac{\sin(\theta)}{1-\cos(\theta)}-\frac{1}{\tan(\theta)} = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)}{1-\cos(\theta)}-\cot(\theta) = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)}{1-\cos(\theta)}-\frac{\cos(\theta)}{\sin(\theta)} = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)*\sin(\theta)}{\sin(\theta)(1-\cos(\theta))}-\frac{\cos(\theta)(1-\cos(\theta))}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\

Part 2

\frac{\sin^2(\theta)}{\sin(\theta)(1-\cos(\theta))}-\frac{\cos(\theta)-\cos^2(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{\sin^2(\theta)-(\cos(\theta)-\cos^2(\theta))}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{\sin^2(\theta)-\cos(\theta)+\cos^2(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\

Part 3

\frac{\sin^2(\theta)+\cos^2(\theta)-\cos(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{1-\cos(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{1}{\sin(\theta)} = \frac{1}{\sin(\theta)} \ \ {\checkmark}\\\\

As the steps above show, the goal is to get both sides be the same identical expression. You should only work with one side to transform it into the other. In this case, the left side transforms while the right side stays fixed the entire time. The general rule is that you should convert the more complicated expression into a simpler form.

We use other previously established or proven trig identities to work through the steps. For example, I used the pythagorean identity \sin^2(\theta)+\cos^2(\theta) = 1 in the second to last step. I broke the steps into three parts to hopefully make it more manageable.

3 0
3 years ago
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