Suppose babies born in a large hospital have a mean weight of 4088 grams, and a variance of 55,696. Of 128 babies are sampled at
random from the hospital, what is the probability that the mean weight of the sample babies would be greater than 4132 grams
1 answer:
Answer:
P = 0.9893
Step-by-step explanation:
The mean weight of the babies born is 4088 and a variance of 55696
This is a sampling question with sample size, n = 128
To find the probability that the mean weight 4088 is greater than 4132
Therefore, probability is given as
P = 4088/4132
P = 0.9893
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