Answer:
a) 0.046 mol/L
b) 0.016 mol
c) 271.58 g/mol
Explanation:
A nonelectrolyte solute is a solute that, when dissolved in a solvent, will not make the solution a conductor, and so the electricity will not pass through it. The osmotic pressure is a colligative property, and it's the pressure difference needed to stop the flow of a solution across a semipermeable membrane. It can be calculated by:
π = MRT
Where π is the osmotic pressure, M is the molarity of the solute (mol/L), R is the ideal gas constant, and T is the temperature (in K). For a pressure in torr, R = 62.3637 torr.L/(mol.K).
a) π = MRT , T = 25°C = 298 K
851 = M*62.3637*298
18584.3826M = 851
M = 0.046 mol/L
b) The number of moles of the solute (n) is the molar concentration (molarity) multiplied by the volume. So, for a solution of 345 mL = 0.345 L,
n = 0.046 * 0.345
n = 0.016 mol
c) The molar mass (MM) is the mass divided by the number of moles:
MM = 4.31/0.016
MM = 271.58 g/mol
Answer:
The height of a column of ethanol is 13.1m
Explanation:
we begin by converting the density to SI unit= <u>0.789g/cm3* 1kg * </u>
<u>* </u>
cm * 1000g * 
= 789kg/m3
converting pressure to SI unit= 1 atm =101325 Pa
hence P= hdg
g= 9.81 m/s2
making h the subject of the formula
h= P/dg
h= 101325Pa/ 789kg/m3 * 9.81 m/s2
h= 13.1m
Here’s one way to do it.
1. Fill the 6 cm cup.
2. Pour its contents into the 10 cm cup. This leaves 4 cm yet to be filled.
3. Refill the 6 cm cup and use it to fill the 10 cm cup. This leaves 2 cm in the 6 cm cup.
4. Empty the 10 cm cup and add the 2 cm from the 6 cm cup.
5. Refill the 6 cm cup.
6. Pour its contents into the 10 cm cup.
The 10 cm cup now contains 8 cm of water.
Answer:
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Explanation:
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Firstly the limiting reactant should be identified. Limiting reactant is the reactant that is in limited supply, the amount of product formed depends on the moles present of the limiting reactant.
the stoichiometry of x to y = 1:2
1 mole of x reacts with 2 moles of y
if x is the limiting reactant, there are 3 moles of x, then 6 moles of y should react, however there are only 4 moles of y. Therefore y is the limiting reactant and x is in excess.
4 moles of y reacts with 2 moles of x
since there are 3 moles of x initially and only 2 moles are used up, excess amount of x is 1 mol thats in excess.
