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3 years ago

751,447 rounded to the nearest 100,000

Mathematics

2 answers:

VARVARA [1.3K]3 years ago

8 0

800,000 because of the 751 at the beginning if it was 749 it would be 700,000

Neko [114]3 years ago

3 0

that would definitely be 800,000 because 751,447 is much more closer to 800,000 than 700,000

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4- A manufacturing process produces items whose weights are normally distributed. It is known that 22.57% of all the items produ

galben [10]

Answer:

$\\ \mu = 118\;grams\;and\;\sigma=30\;grams$

Step-by-step explanation:

We need to use z-scores and a standard normal table to find the values that corresponds to the probabilities given, and then to solve a system of equations to find $\\ \mu\;and\;\sigma$ .

<h3>First Case: items from 100 grams to the mean</h3>

For finding probabilities that corresponds to z-scores, we are going to use here a <u>Standard Normal Table </u><u><em>for cumulative probabilities from the mean </em></u><em>(Standard normal table. Cumulative from the mean (0 to Z), 2020, in Wikipedia) </em>that is, the "probability that a statistic is between 0 (the mean) and Z".

A value of a z-score for the probability P(100<x<mean) = 22.57% = 0.2257 corresponds to a value of z-score = 0.6, that is, the value is 0.6 standard deviations from the mean. Since this value is <em>below the mean</em> ("the items produced weigh between 100 grams up to the mean"), then the z-score is negative.

Then

$\\ z = -0.6\;and\;z = \frac{x-\mu}{\sigma}$

$\\ -0.6 = \frac{100-\mu}{\sigma}$ (1)

<h3>Second Case: items from the mean up to 190 grams</h3>

We can apply the same procedure as before. A value of a z-score for the probability P(mean<x<190) = 49.18% = 0.4918 corresponds to a value of z-score = 2.4, which is positive since it is after the mean.

Then

$\\ z =2.4\;and\; z = \frac{x-\mu}{\sigma}$

$\\ 2.4 = \frac{190-\mu}{\sigma}$ (2)

<h3>Solving a system of equations for values of the mean and standard deviation</h3>

Having equations (1) and (2), we can form a system of two equations and two unknowns values:

$\\ -0.6 = \frac{100-\mu}{\sigma}$ (1)

$\\ 2.4 = \frac{190-\mu}{\sigma}$ (2)

Rearranging these two equations:

$\\ -0.6*\sigma = 100-\mu$ (1)

$\\ 2.4*\sigma = 190-\mu$ (2)

To solve this system of equations, we can multiply (1) by -1, and them sum the two resulting equation:

$\\ 0.6*\sigma = -100+\mu$ (1)

$\\ 2.4*\sigma = 190-\mu$ (2)

Summing both equations, we obtain the following equation:

$\\ 3.0*\sigma = 90$

Then

$\\ \sigma = \frac{90}{3.0} = 30$

To find the value of the mean, we need to substitute the value obtained for the standard deviation in equation (2):

$\\ 2.4*30 = 190-\mu$ (2)

$\\ 2.4*30 - 190 = -\mu$

$\\ -2.4*30 + 190 = \mu$

$\\ \mu = 118$

7 0

2 years ago

Morgan uses 2 oz of dog shampoo to bathe her dog each week. After 4 wk, 34 oz of shampoo remains.

Flauer [41]

The amount of shampoo required by Morgan each week to bathe her dog = 2 oz
So
The amount of shampoo required by Morgan in 7 days to bathe her dog = 2 oz
The amount of shampoo remaining after 4 weeks = 34 oz
So the amount of shampoo remaining after (4 * 7) days = 34 oz
The amount of shampoo remaining after 28 days = 34 oz
The amount of shampoo that Morgan uses in 28 days = (2/7) * 28 oz
= 2 * 4 oz
= 8 oz
Then
8 oz of shampoo is required by Morgan in = 28 days
Then
34 oz of shampoo will be used in = (28/8) * 34 days
= 7 * 17 days
= 119 days
So
The total number of
days before the bottle becomes empty = 119 + 8 oz
= 127 days

6 0

3 years ago

Decide which of the triangles are a right triangle. The figures are now drawn to scale

Kruka [31]

Answer: triangle A

Step-by-step explanation:

Please give me brainliest

3 0

3 years ago

Tell whether the rates are equivalent. 0.4 kilometer for every 15 minutes 0.6 kilometer for every 20 minutes

Ostrovityanka [42]

Answer:

no they are not equivalent

Step-by-step explanation:

0.4/15 = 0.026

so for every minute they travel 0.026km

0.6/20 = 0.03

so for every minute they travel 0.03km

so they are not the same/equivalent

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3 years ago

The table shows the number of each type of toy in the store. the toys will be placed on shelves so that each shelf has the same

skelet666 [1.2K]

First, we compute the highest common factor between the numbers of toys. The highest common factor for 45, 105 and 75 is 15. Therefore, we will need 15 shelves. On each shelf, there will be 45/15 = 3 dolls, 105/15 = 7 footballs and 75/15 = 5 small cars

3 0

3 years ago