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Anvisha [2.4K]
3 years ago
13

751,447 rounded to the nearest 100,000

Mathematics
2 answers:
VARVARA [1.3K]3 years ago
8 0
800,000 because of the 751 at the beginning if it was 749 it would be 700,000
Neko [114]3 years ago
3 0

that would definitely be 800,000 because 751,447 is much more closer to 800,000 than 700,000

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In a certain​ state, 50​% of adults indicated that sausage is their favorite pizza. Suppose a simple random sample of adults in
KatRina [158]

Answer:

n = 23

x = 17

p = 0.50

Step-by-step explanation:

For a binomial experiment we have the following variables:

<u>1) Number of trials or Sample size:</u>

The number of trials is represented by n. In the given scenario 23 adults were asked about their favorite pizza, so the number of trials in this will be 23. Thus

n = 23

<u>2) Number of success</u>

The number of success is denoted by x. Number of success indicates that how many trials resulted in the favorable outcome. In the given case, choosing a sausage pizza is a success. Since 17 adults chose the sausage, so

x = 17

<u>3) Probability of success on single trial</u>

This is represented by p. It is stated that 50% adults say sausage is their favorite pizza. So,

p = 50% = 0.50

4 0
3 years ago
Sara loves to go hiking. This week she hiked 3 miles on Monday, 4 miles on Tuesday, and 3 miles on Thursday. Last week Sara hike
yKpoI14uk [10]
For the answer to the question above, it is just simple and easy. I will the answers directly and the answer is Sara hiked 2 more miles this week than last week.

I hope my answer helped you. Have a nice day!
6 0
3 years ago
Annie is framing a photo with a length of 6 inches and a width of 4 inches. The distance from the edge of the photo to the edge
Ede4ka [16]

Answer:

Part a) The quadratic function is 4x^{2} +20x-39=0

Part b) The value of x is 1.5\ in

Part c) The photo and frame together are 7\ in wide

Step-by-step explanation:

Part a) Write a quadratic function to find the distance from the edge of the photo to the edge of the frame

Let

x----> the distance from the edge of the photo to the edge of the frame

we know that

(6+2x)(4+2x)=63\\24+12x+8x+4x^{2}=63\\ 4x^{2} +20x+24-63=0\\4x^{2} +20x-39=0

Part b) What is the value of x?

Solve the quadratic equation 4x^{2} +20x-39=0

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem

we have

4x^{2} +20x-39=0

so

a=4\\b=20\\c=-39

substitute in the formula

x=\frac{-20(+/-)\sqrt{20^{2}-4(4)(-39)}} {2(4)}

x=\frac{-20(+/-)\sqrt{1,024}} {8}

x=\frac{-20(+/-)32} {8}

x=\frac{-20(+)32} {8}=1.5\ in  -----> the solution

x=\frac{-20(-)32} {8}=-6.5\ in

Part c) How wide are the photo and frame together?

(4+2x)=4+2(1.5)=7\ in

5 0
3 years ago
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shtirl [24]

Answer:

Last one

Step-by-step explanation:

Negative one times 6r is -6r and then that eliminates two of the four. the rest is common sense tbh.... but it is the last one. Hope this helps

3 0
2 years ago
Please answer this question, thx :)
dusya [7]

Answer:

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Step-by-step explanation:

just put into you calculator

47+(15/3)/2

3 0
3 years ago
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