Answer:
506kg
Explanation:
From the reaction equation, we can see that 3 moles of hydrogen yielded 2 moles of ammonia.
Now we need to calculate the number of moles of hydrogen reacted. This mathematically equals the mass of hydrogen reacted divided by the molecular mass of the hydrogen molecule.
The mass of hydrogen reacted is 89.5kg. This equals 89.5 × 1000g which equals 89500g. The molecular mass of hydrogen is 2g/mole ( 1 atom of hydrogen has an atomic mass unit of 1 and 1 molecule of hydrogen has 2 atoms).
Now we mathematically calculate the number of moles of hydrogen reacted to be 89500/2 which equals 44,750 moles.
If 3 moles of hydrogen yielded 2 moles of ammonia gas, then 44, 750 moles will yield 44,750 × (2/3) which equals 29,833 moles of Ammonia gas.
Now, let's calculate the mass of Ammonia gas yielded. This mathematically equals the number of moles of ammonia gas yielded multiplied by the molar mass of ammonia gas. The molar mass of ammonia gas is (14 + 3(1)) which equals 17g/mole.
Hence, the mass yielded equals 29,833 × 17 = 506167g
This equals 506,167 ÷ 1000 = 506.167kg.
Answer:
55.0 g
Explanation:
Step 1: Write the balanced equation for the production of oxygen
2 CO₂(g)⇒ 2 CO(g) + O₂(g)
Step 2: Calculate the mass of oxygen produced over a 2 hour period
The MOXIE produces 10.0 g of oxygen per hour.
2 h × 10.0 g/1 h = 20.0 g
Step 3: Calculate the moles corresponding to 20.0 g of O₂
The molar mass of O₂ is 32.00 g/mol.
20.0 g × 1 mol/32.00 g = 0.625 mol
Step 4: Calculate the number of moles of CO₂ needed to produce 0.625 moles of O₂
The molar ratio of CO₂ to O₂ is 2:1. The moles of CO₂ needed are 2/1 × 0.625 mol = 1.25 mol
Step 5: Calculate the mass corresponding to 1.25 moles of CO₂
The molar mass of CO₂ is 44.01 g/mol.
1.25 mol × 44.01 g/mol = 55.0 g
The theoretical molar yield of lead (II) chloride will be 9 moles.
<h3>Stoichiometric calculation</h3>
First, we need to look at the equation of the reaction:
From the equation, the 1 mole of Pb2+ ion requires 2 moles of Cl- ion in order to produce 1 mole of lead (II) chloride.
Thus, with 18 moles Cl- ions, 9 moles of Pb2+ would be needed, instead of 12 moles. Pb2+ is simply in excess while Cl- can be said to be limiting.
Therefore, Cl- will determine how much of lead (II) chloride that will be produced. The ratio is 2 moles of Cl- to 1 mole of lead (II) chloride.
With 18 moles Cl-, 9 moles of lead (II) chloride will, thus, be produced.
More on mole ratios can be found here: brainly.com/question/14425689
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C. Metals higher in the series will replace metal ions in solution that
are lower in the series.
Explanation:
The activity series of metals shows the extent of reactivity of different metals.
On the activity series, the most reactive metals are located higher up on the able whereas the less reactive ones are found at the bottom of the series.
- We can tell if single displacement reactions will occur by simply looking at the reactivity series.
- Metals that are more reactive will displace the ones that are not very reactive that are positioned down the series. Such a reaction will occur.
- Metals lower in the series cannot displace the ones on top because they are less reactive. Such a reaction will not occur.
Learn more:
Precipitation reaction brainly.com/question/7035326
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The given chemical reaction given above is already balanced such that the number of atoms in the left hand side of the equation is equal to that of the right hand side. Using the dimensional analysis, proper conversion factors and the molar masses,
mass of nitrogen = (0.129 g H₂)(1 mol H₂/2 g H₂)(1 mol N₂/3 mol H₂)(28 g N₂/1 mol N₂)
mass of nitrogen = 0.602 g N₂
Therefore, 0.602 g of nitrogen will be required for he reaction.