Answer:
The independent variable of an experiment is the one that is intentionally changed or manipulated to see the results of changing said variable.
We are told that in each different group, the amount of caffeine that is given to the dog's changes - in the control group, they get no caffeine, in the 2nd group, they get 10 mg of caffeine each, and in the 3rd group, they get 50 mg of caffeine each.
Therefore, since the amount of caffeine that is given to the dogs is the only variable that is being manipulated, this is the independent variable.
Answer:
The limiting reactant is AlCl₃ and the excess reactant is NaOH.
Explanation:
- The balanced equation for the mentioned reaction is:
<em>3NaOH(aq) + AlCl₃(aq) → 3NaCl(aq) + Al(OH)₃(s)↓,</em>
It is clear that 3.0 moles of NaOH(aq) react with 1.0 mole of AlCl₃(aq) to produce 3.0 moles of NaCl(aq) and 1.0 mole of Al(OH)₃(s).
- Firstly, we need to calculate the no. of moles of (8.0 g) of NaOH and (4.0 g) of AlCl₃:
no. of moles of NaOH = mass/molar mass = (8.0 g)/(40.0 g/mol) = 0.2 mol.
no. of moles of AlCl₃ = mass/molar mass = (4.0 g)/(133.34 g/mol) = 0.03 mol.
- From stichiometry; NaOH reacts with AlCl₃ with (3: 1) molar ratio.
∴ 0.09 mol of NaOH (the remaining 1.1 mol is in excess) reacts completely with 0.03 mol of AlCl₃.
<em>the limiting reactant is AlCl₃ and the excess reactant is NaOH.</em>
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Answer:
Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us to identify the required limiting reactant by calculating the moles of water vapor produced by each reactant, CO2 and KOH, as shown below:
In such a way, since 2.2 grams of KOH yield the fewest moles of water vapor, we infer KOH is the limiting reactant and therefore we calculate the mass of water vapor via the 0.0196 moles we obtained:
Regards!
The density is the ratio of the substance's mass to its volume. Density is an extensive property even though mass and volume are both intensive properties. It is because density is constant for each substance at a specified temperature and pressure. The equation is
Density = mass/volume
Substituting the values,
1.40 g/cm³ = [500 mg * (1 g/1000 mg)](Volume)
Volume = 0.357 cm³
