Answer:
We have 12.1 grams of glucose in 100 mL of solution
Explanation:
Step 1: Data given
Mass of glucose = 11.0 grams
Volume = 100 mL
A 55.0 mL sample of this glucose solution was diluted to 0.500 L .
Step 2: Calculate concentration of glucose
Initially, amount of glucose available in 100 ml of the solution = 11.0 grams
Concentration of glucose = mass/ volume
Concentration=11.0 /0.100
= 110 g/L
We take away, 0.055 L of that solution, creating another solution with it but with 0.500 L of volume
Step 3: calculate concentration of the new volume
⇒ with C1 = Concentration of the first solution
⇒ with V1 = Volume of the first solution
⇒ with C2 = Concentration of the second solution
⇒ with V2 = Volume of the second solution
C1V1= C2V2
110 * 0.055= C2 * 0.500
= 12.1 g/L -= the concentration of the new solution
Step 4: Calculate the mass in 0.100 L
Concentration = mass/ volume
12.1 = mass/0.100
=1.21 grams
We have 12.1 grams of glucose in 100 mL of solution
