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igomit [66]
3 years ago
5

Determine whether each cation is acidic or pH-neutral. For the cations that are acidic, write an equation that shows how the cat

ion acts as an acid. a. ��!! b. ��! c. �!�!��! d. ��
Chemistry
1 answer:
Anton [14]3 years ago
6 0

THE COMPLETE QUESTION IS:

Determine whether each cation is acidic or pH-neutral. For those cations that are acidic, write an equation that shows how the cation acts as an acid . a. NH+4 b. Na+ c. Co3+ d. CH2NH+3

Answer:

<em>a. Acidic</em>

<em>b. neutral</em>

<em>c. Acidic</em>

<em>d. Acidic</em>

Explanation:

a. NH4+ + H2O <==> NH3 + H3O+ (NH4+ is a conjugate acid of a weak base. Therefore it is acidic)

b. Neutral. Na+ is a cation of a strong base. Therefore it's pH is neutral.

c. Co(H2O)6³+ + H2O <==>CoH2O5(OH)²+ + H3O+

(Therefore Co+ is a weak acid since hydronium ion is formed.)

d. CH2NH3+ is a conjugate acid of a weak base. Therefore it is acidic.

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Answer:

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Explanation:

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In writing an ionic equation, only the aqueous compounds dissociates into ions. This means HCl and ZnCl2 would dissociate to form ions.

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The correct option is;

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For the gas phase decomposition of 1-bromopropane, CH3CH2CH2BrCH3CH=CH2 + HBr the rate constant at 622 K is 6.43×10-4 /s and the
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<span>Answer is: activation energy of this reaction is 212,01975 kJ/mol.
Arrhenius equation: ln(k</span>₁/k₂) = Ea/R (1/T₂ - 1/T₁<span>).
k</span>₁<span> = 0,000643 1/s.
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T₁ = 622 K.

T₂ = 666 K.

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1/T₁<span> = 1/622 K = 0,0016 1/K.
1/T</span>₂<span> = 1/666 K = 0,0015 1/K.
ln(0,000643/0,00828) = Ea/8,3145 J/Kmol · (-0,0001 1/K).
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Ea = 212019,75 J/mol = 212,01975 kJ/mol.</span>

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The molar mass units are always g/mol

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