The answer is 250 inches 3
Answer:
This is required answer.
Explanation:
Given that:
1. by addition the ammonia to acetic acid
using balanced chemical equation:
ammonium acetate:
The balanced equation is:
NH₃ + H₂O ===> NH₄OH
when ammonia gas dissolves in water then we get the base in form of ammonium hydroxide.
When NH₄OH reacts with CH₃COOH then we get ammonium acetate and water
NH₄OH + CH₃COOH ===> [CH₃COO]- & NH₄+ & H₂O
So, we can say that,
when we are adding an acid and a base together then we get the product of H₂O and given elements.
2. addition of barium hydroxide to sulfuric acid:
The balanced equation is :
H₂SO4+ Ba(OH)₂--> BaSO₄+ 2H₂O
when acid and base reacts together than we get barium sulphate and water
when sulfuric acid and barium hydroxide.
Hence, this is required answer.
Answer:
2.3x10⁷ W/m²
Explanation:
The intensity (I) of a laser is its potency (P) divided by the area (A) that it is affected. The potency is the energy applied (or absorbed) in a period, thus id 91.0% of the energy is absorbed, so:
E = 0.91*540 = 491.4 J
And,
P = E/t, where t is the time in seconds
P = 491.4/4.00
P = 122.85 J/s
P = 122.85 W
The are of a circular spot is:
A = (π/4)*d²
Where d is the diameter. Thus, with d = 2.60 mm = 0.0026 m
A = (π/4)*(0.0026)²
A = 5.31x10⁻⁶ m²
I = P/A
I = 122.85/5.31x10⁻⁶
I = 2.3x10⁷ W/m²
the balanced equation for the acid base reaction is
KOH + HClO₄ ---> KClO₄ + H₂O
stoichiometry of KOH to HClO₄ is 1:1
The number of HClO₄ moles - 0.723 M / 1000 mL/L x 25.0 mL = 0.0181 mol
Number of KOH moles - 0.27 M/ 1000 mL/L x 80.0 mL = 0.0216 mol
KOH is a strong acid and HClO₄ is a strong base therefore complete dissociation takes place.
acid reacts with base in 1:1 molar ratio, there's excess base remaining.
excess OH⁻ ions - 0.0216 - 0.0181 = 0.0035 mol
concentration is calculated as number of moles/volume
volume of solution - 25.0 + 80.0 = 105.0 mL
[OH⁻] = 0.0035 mol / 0.105 L = 0.033 M
pOH = -log [OH⁻]
pOH = -log(0.033 M)
pOH = 1.48
pH can be calculated by knowing pOH
pH + pOH = 14
pH = 14 - 1.48 = 12.52
pH = -log [H₃O⁺]
[H₃O⁺] = antilog(-12.52)
[H₃O⁺] = 3.0 x 10⁻¹³ M
Answer is 3 x 10⁻¹³ M
