Looks correct but the second to last I would of put abiotic and biotic factors but I don’t know what’s right for you
Answer:
37.8 L OF CARBON MONOXIDE IS REQUIRED TO PRODUCE 18.9 L OF NITROGEN.
Explanation:
Equation for the reaction:
2 CO + 2 NO ------> N2 + 2 CO2
2 moles of carbon monoxide reacts with 2 moles of NO to form 1 mole of nitrogen
At standard temperature and pressure, 1 mole of a gas contains 22.4 dm3 volume.
So therefore, we can say:
2 * 22.4 L of CO produces 22.4 L of N2
44.8 L of CO produces 22.4 L of N2
Since, 18.9 L of Nitrogen is produced, the volume of CO needed is:
44.8 L of CO = 22.4 L of N
x L = 18.9 L
x L = 18.9 * 44.8 / 22.4
x L = 18.9 * 2
x = 37.8 L
The volume of Carbon monoxide required to produce 18.9 L of N2 is 37.8 L
Answer:
Volume of NCl3 is 3L
Explanation:
Avogadro states: All gases at the same volume under temperature and pressure constant have the same number of moles.
The chemical equation is:
3Cl2(g) + N2(g) → 2NCl3(g)
Where 3 moles of chlorine reacts with 1 mole of nitrogen to produce 2 moles of NCl3.
But using Avogadros law we can say:
3L of chlorine and 1L of nitrogen produce 2L of Nitrogen trichloride.
3L of chlorine and 1L of nitrogen: 4L (The stoichiometric mixture)
That means, volume of NCl3 produced is 3L
