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mars1129 [50]
3 years ago
7

Classify the same processes as exothermic or endothermic.

Chemistry
2 answers:
Inessa [10]3 years ago
8 0

Answer:

1.endothermic

2.exothermic

3.exothermic

RSB [31]3 years ago
5 0

Answer:

1. Endothermic

2. Exothermic

3. Exothermic

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A laser used to read CDs emits red light of wavelength 700 nm. How many photons does it emit each second if its power is?(a) 0.1
Elenna [48]

power = work/time

watt = joule/sec

a) power = 0.10 watt = 0.1joules/sec

work = power * time

= 0.10 * 1 =0.1joules

work is northing but energy

therefore energy is 0.1joules

according to planks quantum theory E = nhν where nis the no. of photons ; h is planks constant; ν isfrequency

hence, n = E/hν

or n = Eλ/hc (ν = c/λ)

n = (0.1*700*10^-9)/6.625*10^-34*3*10^8 = 0.3522*10^18photons

b) similar to the above calculation

here E = 1.0joules

n = (1.0*700*10^-9)/6.625*10^-34*3*10^8 = 0.3522*10^17photons

4 0
3 years ago
What is the velocity of a wave traveling north with a frequency of 75 hertz and a wavelength of
Vanyuwa [196]

Answer:

v = 450 m/s

Explanation:

Given data:

Frequency = 75 Hz

Wavelength = 6 m

Velocity = ?

Solution:

Velocity is the product of frequency and wavelength.

v = f × λ

v = 75 Hz ×  6 m

Hz = s⁻¹

v = 75  s⁻¹  ×  6 m

v = 450 m/s

3 0
3 years ago
If your school said no rules wut would you do
VLD [36.1K]

Answer:

please add more info into your response

Explanation:

6 0
2 years ago
______ is a chemical property of matter.
Reika [66]
I think it’s chemical reactivity
4 0
3 years ago
A 25.0-mL sample containing Cu2+ gave an instrument signal of 25.2 units (corrected for a blank). When exactly 0.500 mL of 0.027
irga5000 [103]

Answer:

The molar concentration of Cu²⁺ in the initial solution is 6.964x10⁻⁴ M.

Explanation:

The first step to solving this problem is calculating the number of moles of Cu(NO₃)₂ added to the solution:

C = \frac{n}{V} \\0.0275 = \frac{n}{0.0005} \\

n = 1.375x10⁻⁵ mol

The second step is relating the number of moles to the signal. We know the the n calculated before is equivalent to a signal increase of 19.9 units (45.1-25.2):

1.375x10⁻⁵ mol _________ 19.9 units

        x              _________  25.2 units

x = 1.741x10⁻⁵mol

Finally, we can calculate the Cu²⁺ concentration :

C = 1.741x10⁻⁵mol / 0.025 L

C = 6.964x10⁻⁴ M

7 0
3 years ago
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