Answer:
c) that the formation and decomposition of ES is the same for a period of time
Explanation:
Michaelis-Menten equation :
This model explain the approach to enzyme kinetics.The Equation shows how a Free enzyme E and Product P is formed depicting by Following equation.
E+S⇌ES→E+P
Left side represents
E =enzyme
S=substrate
ES=enzyme-substrate complex
Right side
E= Free enzyme
P= product
c) that the formation and decomposition of ES is the same for a period of time
Answer:
and 
and 
and 
and 
Explanation:
According to the Bronsted-Lowry conjugate acid-base theory, an acid is defined as a substance which looses donates protons and thus forming conjugate base and a base is defined as a substance which accepts protons and thus forming conjugate acid.
For the given chemical equations:
1. 
Here,
is loosing a proton, thus it is considered as an acid and after losing a proton, it forms
which is a conjugate base.
2. 
Here,
is loosing a proton, thus it is considered as an acid and after losing a proton, it forms
which is a conjugate base.
3. 
Here,
is loosing a proton, thus it is considered as an acid and after losing a proton, it forms
which is a conjugate base.
4.
and
are not conjugate acid/ base pairs.
5. 
Here,
is loosing a proton, thus it is considered as an acid and after losing a proton, it forms
which is a conjugate base.
Answer:
26.33 g of NO.
Explanation:
We'll begin by writing the balanced equation to produce NO from H2O. This is given below:
5N2 + 6H2O —> 4NH3 + 6NO
Next, we shall determine the mass of H2O that reacted and the mass of NO produced from the balanced equation. This is illustrated below:
Molar mass of H2O = (2x1) + 16 = 18 g/mol
Mass of H2O from the balanced equation = 6 x 18 = 108 g
Molar mass of NO = 14 + 16 = 30 g/mol
Mass of NO from the balanced equation = 6 x 30 = 180 g
From the balanced equation above,
108 g of H2O reacted to produce 180 g of NO.
Finally, we shall determine the mass of NO produced by the reaction of 15.8 g of H2O.
This is illustrated below:
From the balanced equation above,
108 g of H2O reacted to produce 180 g of NO.
Therefore, 15.8 g of H2O will react to produce = (15.8 x 180)/108 = 26.33 g of NO.
Therefore, 26.33 g of NO were obtained from the reaction.
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