PH is the potential of hydrogen, pH provides a measure of the concentration of hydrogen ion while pOH scale provides the concentration of OH- ions.
pH denotes the negative logarithm of concentration of hydrogen while pOH denotes the negative logarithm of the concentration OH- ions.
Therefore; in this case the pOH= -log (OH-)
= - log (10^-10)
= 10
If the pOH is 10 then the pH of the solution will be 4
<span>1.02x10^2 ml
Since molarity is defined as moles per liter, the product of the molarity and volume will remain constant as mole solvent is added. So let's set up an equality to express this
m0*v0 = m1*v1
where
m0, v0 = molarity and volume of original solution
m1, m1 = molarity and volume of final solution.
Solve for v0, then substitute the known values and calculate:
m0*v0 = m1*v1
v0 = (1.75 M * 500 ml)/8.61 M
v0 = (1.75 M * 500 ml)/8.61 M
V0 = 101.6260163
Rounding to 3 significant figures gives 102 ml.
So the original volume of the 8.61 M H2SO4 solution was 102 ml or 1.02x10^2 ml.</span>
Answer:
B
Explanation:
well heterogenous mixtures are not uniformly distributed these meaning whatever components are "mixed" can be seperated easily
a example of this can be
Soil, oil in water, ice in water
while Homogeneous mixture cannot be seen seperated
The element with 4 protons in the nucleus in Beryllium.
