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Otrada [13]
3 years ago
9

If a sample of Fe2S3 contains 1.25x10ˣ15 iron atoms what is the mass in grams?

Chemistry
1 answer:
VMariaS [17]3 years ago
4 0

Answer:

mass = 0.00000043189g

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N₂O(g) + 3 H₂(g) N₂H4(1) + H₂O(1) AH = -317 kJ/mol
docker41 [41]

Answer:

A

Explanation:

Recall that Δ<em>H</em> is the sum of the heats of formation of the products minus the heat of formation of the reactants multiplied by their respective coefficients. That is:


\displaystyle \Delta H^\circ_{rxn} = \sum \Delta H^\circ_{f} \left(\text{Products}\right) - \sum \Delta H^\circ_{f} \left(\text{Reactants}\right)

Therefore, from the chemical equation, we have that:


\displaystyle \begin{aligned} (-317\text{ kJ/mol}) = \left[\Delta H^\circ_f \text{ N$_2$H$_4$} +  \Delta H^\circ_f \text{ H$_2$O}  \right]   -\left[3 \Delta H^\circ_f \text{ H$_2$}+\Delta H^\circ_f \text{ N$_2$O}\right] \end{aligned}

Remember that the heat of formation of pure elements (e.g. H₂) are zero. Substitute in known values and solve for hydrazine:

\displaystyle \begin{aligned} (-317\text{ kJ/mol}) & = \left[ \Delta H^\circ _f \text{ N$_2$H$_4$} + (-285.8\text{ kJ/mol})\right] -\left[ 3(0) + (82.1\text{ kJ/mol})\right] \\ \\ \Delta H^\circ _f \text{ N$_2$H$_4$} & = (-317 + 285.8 + 82.1)\text{ kJ/mol} \\ \\ & = 50.9\text{ kJ/mol} \end{aligned}

In conclusion, our answer is A.

5 0
2 years ago
Which is a chemical property of soda ash? A.It's a highly basic substance. B.It's a white crystalline powder. It can dissolve in
LenaWriter [7]
A) its a highly basic substance
5 0
3 years ago
Read 2 more answers
How would you ask a girl out. I know that I can use my voice, but I don’t know what to say.
kirill [66]

Answer:

Just go out there and be yourself brother!

Explanation:

If she doesn't like you, she doesn't like the real you, therefore you don't deserve her! lol

4 0
3 years ago
A particular brand of gasoline has a density of 0.737 g/ml at 25 ∘c. how many grams of this gasoline would fill a 13.0 gal tank
Usimov [2.4K]

Density of gasoline is 0.737 g/mL and volume of tank is 13.0 gal.

Since, 1 US gal=3.78 L

Volume of tank in L will be:

V=13.0 gal(\frac{3.78 L}{1 gal})=49.14 L

Also, 1 L=1000 mL

Thus,

V=49.14 L(\frac{1000 mL}{1 L})=49140 mL

Mass of gasoline can be calculated as follows:

m=d×V

Here, d is density and V is volume thus,

m=0.737 g/mL\times 49140 mL=3.62\times 10^{4}g

Therefore, mass of gasoline will be 3.62\times 10^{4}g.

7 0
3 years ago
What do Ivan Pavlov and Erik Erikson have in common?
Vikentia [17]

Answer:

I don't know the exact answer you are looking for

7 0
3 years ago
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