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balu736 [363]
3 years ago
13

Using the following equation for the combustion of octane, calculate the heat associated with the formation of 100.0 g of carbon

dioxide. The molar mass of octane is 114.33 g/mol. The molar mass of carbon dioxide is 44.0095 g/mol.
Chemistry
1 answer:
givi [52]3 years ago
7 0

Answer: Heat associated with the formation of 100.0 g of carbon dioxide is 1563.2 kJ.

Explanation:

Reaction equation will be as follows.

    2C_{8}H_{18} + 25O_{2} \rightarrow 16CO_{2} + 18H_{2}O;  \Delta H^{o}_{rxn} = -11018 kJ

Mass of CO_{2} = 100 g

Hence, moles of CO_{2} present will be calculated as follows.

       No. of moles = \frac{mass}{\text{molar mass}}

                             = \frac{100 g}{44.0095 g/mol}

                             = 2.27 mol

Therefore, heat produced by 2.27 mol for the given reaction will be calculated as follows.

         2.27 mol \times \frac{11018 kJ}{16 mol CO_{2}}

             = 1563.2 kJ

Thus, we can conclude that heat associated with the formation of 100.0 g of carbon dioxide is 1563.2 kJ.

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Elenna [48]

Water decomposes when electrolyzed to produce hydrogen and oxygen gas. If 2.5 grams of water were decomposed 1.04 grams of oxygen will be formed.

BCA table:

2H_{2}O ⇒ H_{2} + O_{2}

B  0.13        0 + 0

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Explanation:

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B  0.13        0 + 0

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A  0             0.065

Number of moles of water = \frac{mass}{atomic mass of 1 mole}

mass = 2.5 grams

atomic mass= 18 grams

number of moles can be known by putting the values in the formula,

n = \frac{2.5}{18}

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2 moles of water gives one mole of oxygen on decomposition

so, 0.13 moles of water will give x moles of oxygen on decompsition

\frac{1}{2} = \frac{x}{0.13}

x = 0.065 moles of oxygen will be formed.

moles to gram will be calculated as

mass =number of moles x atomic mass

        = 0.065 x 16

         = 1.04 grams of oxygen.

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Answer:

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