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AnnyKZ [126]
4 years ago
13

What type of motion occurs when an object spends around and axis without altering its linear position?

Physics
2 answers:
exis [7]4 years ago
8 0
Well there has to have a altering linear position
lara [203]4 years ago
6 0
Is there an alter lining
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Natasha_Volkova [10]

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The answer to this is:

True:

✯ EXPLANATION:

Because Dissociative identity disorder, do wandering away from home from they depression, they parents always fighting, having bad grades in school. having a different change about you. Having about they anger, and about they mentally emotionally.

Hope It Helped!

And tell me if The answer is wrong. . .

Good Luck With Your Assignment!

#LearnWithBrainly

Answer:

- TanakaBro

7 0
3 years ago
Read 2 more answers
A particle of mass m= 2.5 kg has velocity of v = 2 i m/s, when it is at the origin (0,0). Determine the z- component of the angu
melomori [17]

Answer:

please read the answer below

Explanation:

The angular momentum is given by

|\vec{L}|=|\vec{r}\ X \ \vec{p}|=m(rvsin\theta)

By taking into account the angles between the vectors r and v in each case we obtain:

a)

v=(2,0)

r=(0,1)

angle = 90°

L=(2.5kg)(1)(2\frac{m}{s})sin90\°=5.0kg\frac{m}{s}

b)

r=(0,-1)

angle = 90°

L=(2.5kg)(1)(2\frac{m}{s})sin90\°=5.0kg\frac{m}{s}

c)

r=(1,0)

angle = 0°

r and v are parallel

L = 0kgm/s

d)

r=(-1,0)

angle = 180°

r and v are parallel

L = 0kgm/s

e)

r=(1,1)

angle = 45°

L = (2.5kg)(2\frac{m}{s})(\sqrt{2})sin45\°=5kg\frac{m}{s}

f)

r=(-1,1)

angle = 45°

the same as e):

L = 5kgm/s

g)

r=(-1,-1)

angle = 135°

L=(2.5kg)(2\frac{m}{s})(\sqrt{2})sin135\°=5kg\frac{m}{s}

h)

r=(1,-1)

angle = 135°

the same as g):

L = 5kgm/s

hope this helps!!

4 0
4 years ago
A diver, of mass 40kg, climbs up to a diving platform 1.25m high. What’s her KE
Leona [35]

Explanation:

The formula for KE ( Kinetic Energy ) is : 1/2 mv²

Solution:

  • First we solve for v ( velocity ) using the formula 2gh, where g is gravity [ 9.8 m/s² ] and h is height [ 1.25 m ]

= 2 ( 9.8 m/s² × 1.25 m ) = 24.5 m/s

  • The velocity is 24.5 m/s.

  • Now solve for KE using the formula 1/2 mv²

= 1/2 ( 40 kg × 24.5m/s ² )

= 1/2 ( 40 kg × 600.25 )

= 1/2 ( 24,010 )

= 12,005 Joules

  • The diver's kinetic energy is 12,005 J.

6 0
2 years ago
Which statement describes an essential characteristic of data in an experiment?
MAVERICK [17]
The whole of the data that you have researched on
3 0
4 years ago
Read 2 more answers
An artificial satellite of mass 900kg Is launched at a speed of 11,000 m/s from its launching station. How much is the kinetic e
Marina CMI [18]

Answer:

KE = 54450 J

Explanation:

Data:

  • m = 900 kg
  • v = 11.000 m/s
  • KE = ?

Use the formula:

  • \boxed{\bold{K_{E}=\frac{m*(v)^{2}}{2}}}

Replace and solve:

  • \boxed{\bold{K_{E}=\frac{900\ kg*(11.000\frac{m}{s})^{2}}{2}}}
  • \boxed{\bold{K_{E}=\frac{900\ kg*121\frac{m^{2}}{s^{2}}}{2}}}
  • \boxed{\bold{K_{E}=\frac{108900\ J}{2}}}
  • \boxed{\boxed{\bold{K_{E}=54450\ J}}}

A kinetic energy of <u>54450 Newtons</u> is imparted to it.

Greetings.

6 0
3 years ago
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