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Nata [24]
3 years ago
11

Ricardo, mass 85 kg, and Carmelita, who is lighter, are enjoying Lake Merced at dusk in a 20 kg canoe. When the canoe is at rest

in the placid water, they exchange seats, which are 3.0 m apart and symmetrically located with respect to the canoe's center. Ricardo notices that the canoe moved 35 cm relative to a submerged log during the exchange and calculates Carmelita's mass, which she has not told him. What is it?
Physics
1 answer:
diamong [38]3 years ago
6 0

Answer:

65.14925 kg

Explanation:

Center of mass before the exchange

X_{c1}=\dfrac{0+1.5\times 20+3\times 85}{85+20+x}

Center of mass after exchange

X_{c2}=\dfrac{0.35\times 85+(0.35+1.5)\times 20+(3+0.35)\times x}{85+20+x}

The center of mass remains constant so X_{c1}=X_{c2}

\dfrac{0+1.5\times 20+3\times 85}{85+20+x}=\dfrac{0.35\times 85+(0.35+1.5)\times 20+(3+0.35)\times x}{85+20+x}\\\Rightarrow 1.5\times 20+3\times 85=0.35\times 85+(0.35+1.5)\times 20+(3+0.35)\times x\\\Rightarrow x=\dfrac{1.5\times 20+3\times 85-0.35\times 85-(0.35+1.5)\times 20}{3+0.35}\\\Rightarrow x=65.14925\ kg

Mass of Carmelita is 65.14925 kg

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Answer:

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Explanation:

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\Delta t = \gamma \Delta t'\\\\\Delta t = \frac{1}{\sqrt{1-\frac{v^2}{c^2}}}\times \frac{\Delta t}{2}\\\\\sqrt{1-\frac{v^2}{c^2}} =\frac{1}{2}\\\\1-\frac{v^2}{c^2}=\frac{1}{4}\\\\\frac{3}{4}c^2 = v^2\\\\v = 0.87 c

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hope it helps .

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