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elixir [45]
2 years ago
12

A 3m plank AB of mass 20kg has a center of gravity 2m from end A and rests on supports R1 and R2 both 0,5m from either end. It a

lso carries a 10kg block at end A. Calculate the reactions at R1 and R2
Physics
1 answer:
postnew [5]2 years ago
5 0

Answer:

130.7 N

Explanation:

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The human eye can readily detect wavelengths from about 400 nm to 700 nm. If white light illuminates a diffraction grating havin
nadya68 [22]

Answer:

The range of angles is from 17.50° to 31.76°

Explanation:

The diffraction grid equation is as follows:

dsen\theta=m\lambda

Clearing for \theta

sen\theta=\frac{m\lambda}{d}

\theta=sen^{-1}(\frac{m\lambda}{d})

where \theta is the angle, m is the order, in this case m=1, \lambda is the wavelength, and d is defined as follows:

d=\frac{1}{resolution}

and since the resolution is 750 lines/mm wich is the same as 750lines/1x10^{-3}m

d will be:

d=\frac{1}{750lines/1x10^{-3}m}=\frac{1x10^{-3}m}{750lines}=1.33x10^{-6}m

wich is the distance between each line of the diffraction grating.

substituting the values for m and d:

\theta=sen^{-1}(\frac{(1)\lambda}{(1.33x10^{-6}m)})

And we need to find two angle values: one for when the wavelength is 400nm and one for when it is 700 nm. So we will get the angle range

\theta=sen^{-1}(\frac{(400x10^{-9})}{(1.33x10^{-6}m)})=17.50

and

\theta=sen^{-1}(\frac{(700x10^{-9})}{(1.33x10^{-6}m)})=31.76

The range of angles is from 17.50° to 31.76°

3 0
3 years ago
Si dos aparatos eléctricos que tienen diferente potencia funcionan durante el mismo tiempo, ¿ cual transformara mayor cantidad d
Brilliant_brown [7]

Answer: I dont undertand sorry

Explanatio

5 0
3 years ago
In Rutherford's experiment, which of the following proved that the
vampirchik [111]

Answer:

b) the alpha particles were found to be attracted to the nucleus

Explanation:

5 0
3 years ago
the atomic number of cesium (Cs) is 55. If an atom of cesium has 78 neutrons, what is the atomic mass of cesium?
Slav-nsk [51]
Atomic mass= number of protons + number of neutrons
55 + 78 = 133
hope this helps
7 0
3 years ago
Read 2 more answers
he membrane that surrounds a certain type of living cell has a surface area of 6.0 x 10-9 m2 and a thickness of 1.6 x 10-8 m. As
k0ka [10]

Answer:

1.54481175\times 10^{-12}\ C

Explanation:

\epsilon_0 = Permittivity of free space = 8.85\times 10^{-12}\ F/m

A = Area = 6\times 10^{-9}\ m^2

d = Thickness = 1.6\times 10^{-8}\ m

k = Dielectric constant = 5.4

V = Voltage = 86.2 mV

Charge is given by

Q=CV\\\Rightarrow Q=k\epsilon\dfrac{A}{d}V\\\Rightarrow Q=5.4\times 8.85\times 10^{-12}\times \dfrac{6\times 10^{-9}}{1.6\times 10^{-8}}\times 86.2\times 10^{-3}\\\Rightarrow Q=1.54481175\times 10^{-12}\ C

The charge on the outer surface is 1.54481175\times 10^{-12}\ C

4 0
3 years ago
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