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cestrela7 [59]
3 years ago
13

Detailed measurements of the disk and central bulge region of our Galaxy suggest our Milky Way is a:Select one:A. quasar. B. bar

red spiral galaxy. C. very flat elliptical galaxy. D. very dusty irregular galaxy. E. normal spiral galaxy.
Physics
1 answer:
chubhunter [2.5K]3 years ago
4 0

I believe the answer is:

~D. Very dusty irregular galaxy.

Hope this helps!!!

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What is the relationship that exist between the mole molar mass and avogadro number?
Elenna [48]
Avogadros number is the definition of a mole. SO a mole is 1 avogadros number of atoms. molar mass is how much 1 avogadros number of atoms weighs. each element on the periodic table has a different mass, so 1 mole of each of the elements has a different molar mass.
7 0
3 years ago
Do you have a lawn mower engine running for 20 minutes does 4,560, 000 J of work. What is the power output of the engine?
alekssr [168]

Answer:

P = 3800 W

Explanation:

Power is equal to energy divide by time P = E/t

plug in 4560000 J for energy

convert 20 minutes to seconds

20 * 60 = 1200 seconds

plug in 1200 seconds for time

P = 4560000/1200

P = 3800 W

7 0
3 years ago
Are you going to finish that CROISSANT?
jeyben [28]

Answer:

you almost made me drop my croissant

Explanation:

<3

5 0
3 years ago
Read 2 more answers
Write 8.54 x 103 in standard notation<br> a. 854,000<br> b. 85,400<br> c. 8,540<br> d. 854
weeeeeb [17]
B. 8540, (assuming you meant 8.54 x 10 to the power 3) you move the decimal point 3 places to the right, if the decimal point can't pass any more numbers add zeros. If it confuses you to think of it this way do 10 cubed first, i.e. 10 x 10 x10 = 1000 and then do 8.54 x 1000 if thats easier for you.
5 0
3 years ago
A block of mass m moving due east at speed v collides with and sticks to a block of mass 2m that is moving at the same speed vv
lapo4ka [179]

Answer:

30.36°

Explanation:

By using linear momentum; linear momentum can be expressed by the relation:

mv_xi + mv_yj

where ;

m= mass

v_x = velocity of components in the x direction

v_y = velocity of components in the y direction

If we consider the east as the positive x and north as positive y which is synonymous to what we usually have on a graph.

Then;

Initial momentum = mvi + 2mvcos 45i + 2mvsin45 j

= (mv+2mvcos45)i + (2mvsin45)j

However, the masses stick together after collision and move with a common velocity: V_xi +V_yj

∴ Final momentum = 3mv (V_xi +V_yj)

= 3mV_xi + 3mV_yj

From the foregoing ;

initial momentum = final momentum

3mV_xi + 3mV_yj = (mv+2mvcos45)i+(2mvsin45j)

So;

3mV_x = mv + 2mv cos 45 \\\\3mV_y = 2mV sin 45

V_x = \frac{mv+2mvcos45 }{3m}\\\\V_x = \frac{v+2vcos45}{3}

V_y = \frac{2mvsin45}{3m} \\\\V_y = \frac{2vsin45}{3}

Finally;

The required angle θ = tan^{-1} = \frac{V_y}{V_x}

θ = tan^{-1} = \frac{\frac{2vsin45}{3}}{\frac{v+2v.cos45}{3}}

θ = tan^{-1} = \frac{2sin 45}{1+2cos45}\\\\

θ = 30.36°

7 0
3 years ago
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