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lidiya [134]
3 years ago
12

Students in an introductory physics lab are performing an experiment with a parallel-plate capacitor made of two circular alumin

um plates, each 21 cm in diameter, separated by 1.0 cm . Part A How much charge can be added to each of the plates before a spark jumps between the two plates? For such flat electrodes, assume that value of 3× 10 6 N/C of the field causes a spark. Express your answer with the appropriate units. q max q m a x = nothing nothing SubmitRequest Answer Provide Feedback Next
Physics
1 answer:
Alex777 [14]3 years ago
7 0

Answer:

0.92 μC

Explanation:

In a parallel-plate capacitor, the electric field formed is equal to the charge density divited by the vacuum permisivity e0, as there are no dielectric between the plates. e0 is equal to 8.85*10^-12 C^2/Nm^2. The charge density is the total charge of each individual plate divided by its area. Then, the maximum charge allowed will be equal to:

E = \frac{o}{e_0} = \frac{Q}{Ae_0} \\ Q = E*A*e_0 = 3*10^6 N/C * (0.25*\pi *(0.21m)^2)*8.85*10^{-12}C^2/Nm^2 = 9.196 *10^{-7} C

or 0.92 μC

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katen-ka-za [31]

No, there are not any carbon atoms inside this compound.

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Thus, none of the elements in this compound are carbon, meaning there are no carbon atoms. Let me know if you need any clarifications, thanks!

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The most likely items to be used are;

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A wave of infrared light has a speed of 6m/s and a wave length of 12 m. What is the frequency of this wave?
erastovalidia [21]
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6 0
4 years ago
Train cars are coupled together by being bumped into one another. Suppose two loaded train cars are moving toward one another, t
stellarik [79]

Answer:

0.243 m/s

Explanation:

From law of conservation of motion,

mu+m'u' = V(m+m')................. Equation 1

Where m = mass of the first car, m' = mass of the second car, initial velocity of the first car, u' = initial velocity of the second car, V = Final velocity of both cars.

make V the subject of the equation

V = (mu+m'u')/(m+m')................. Equation 2

Given: m = 260000 kg, u = 0.32 m/s, m' = 52500 kg, u' = -0.14 m/s

Substitute into equation 2

V = (260000×0.32+52500×(-0.14))/(260000+52500)

V = (83200-7350)/312500

V = 75850/312500

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3 years ago
Cliff divers at Acapulco jump into the sea from a cliff 37.1 m high. At the level of the sea, a rock sticks out a horizontal dis
Stella [2.4K]

Answer:

v_x = 4.87 m/s

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Height of the cliff is given as

h = 37.1 m

now the time taken by the diver to hit the surface is given as

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v_x = \frac{13.39}{2.75}

v_x = 4.87 m/s

3 0
4 years ago
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