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3 years ago

Find the volume of a prism

Mathematics

2 answers:

nalin [4]3 years ago

5 0

Answer:

Volume of prism

= base area × height

drek231 [11]3 years ago

5 0

Answer:

Assume a rectangular prism

Dimensions: length,l; width,w; height,h

Step-by-step explanation:

Volume,V=

$Volume,V=l\times w \times h \\ = lwh$

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You run 6 miles in one hour at this rate how long will it take you to run a marathon approximately 26 mile

Shalnov [3]

Divide 26 by 6 to get 4.33. Divide 60 by 3 to get 20.

It will take approximately 4 hours and 20 minutes to run the marathon.

5 0

3 years ago

Help me please please

Ivan

Answer: 11

============================================

Explanation:

Point C is the circumcenter of triangle PQR. This means that we can draw a circle centered at C that goes through points P, Q and R at the same time. This circle has a special name: circumcircle.

The segments PC, RC and QC are all radii, so they are the same length. Pick two of the given expressions and set them equal to one another. Then solve for x

I'm going to pick the expressions for PC and RC

PC = RC
3x+7 = 5x-15
5x-3x = 7+15
2x = 22
x = 22/2
x = 11

5 0

3 years ago

Dan bought 6 new baseball trading cards to add to his collection. The next day, his dog ate half of his collection. There are no

Vika [28.1K]

Answer:

50 cards

Step-by-step explanation:

28*2= 56

56-6=50

3 0

2 years ago

Read 2 more answers

A 1/17th scale model of a new hybrid car is tested in a wind tunnel at the same Reynolds number as that of the full-scale protot

Olegator [25]

Answer:

The ratio of the drag coefficients $\dfrac{F_m}{F_p}$ is approximately 0.0002

Step-by-step explanation:

The given Reynolds number of the model = The Reynolds number of the prototype

The drag coefficient of the model, $c_{m}$ = The drag coefficient of the prototype, $c_{p}$

The medium of the test for the model, $\rho_m$ = The medium of the test for the prototype, $\rho_p$

The drag force is given as follows;

$F_D = C_D \times A \times \dfrac{\rho \cdot V^2}{2}$

We have;

$L_p = \dfrac{\rho _p}{\rho _m} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_m} \right)^2 \times L_m$

Therefore;

$\dfrac{L_p}{L_m} = \dfrac{\rho _p}{\rho _m} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_m} \right)^2$

$\dfrac{L_p}{L_m} =\dfrac{17}{1}$

$\therefore \dfrac{L_p}{L_m} = \dfrac{17}{1} =\dfrac{\rho _p}{\rho _p} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_p} \right)^2 = \left(\dfrac{V_p}{V_m} \right)^2$

$\dfrac{17}{1} = \left(\dfrac{V_p}{V_m} \right)^2$

$\dfrac{F_p}{F_m} = \dfrac{c_p \times A_p \times \dfrac{\rho_p \cdot V_p^2}{2}}{c_m \times A_m \times \dfrac{\rho_m \cdot V_m^2}{2}} = \dfrac{A_p}{A_m} \times \dfrac{V_p^2}{V_m^2}$