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kiruha [24]
3 years ago
10

What type of chemical bond can form between an atom with 11 protons and an atom with 17 protons? what type of chemical bond can

form between an atom with 11 protons and an atom with 17 protons? non-polar covalent ionic hydrogen polar covalent?
Chemistry
2 answers:
asambeis [7]3 years ago
8 0
Ionic non polar is correct
Aloiza [94]3 years ago
5 0

atomic number of elements are the number of protons

in neutral atoms number of protons are equal to number of electrons

electrons are responsible for the chemical bonding in atoms

bonding depends on the number of valence electrons in the outermost shells.

atom A with 11 protons have 11 electrons, electronic configuration is - 2,8,1

atom B with 17 protons have 17 electrons, electron configuration is - 2,8,7

A has 1 valence electron and B has 7 valence electrons

therefore A prefers to give away its one valence electron and have a complete outer shell and B prefers to take in that one electron from A to become a complete octet.

The type of bond is an ionic bond formed by the transfer of electrons from one species to another species

answer is ionic



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A 2.2 M solution is made by with 0.45 moles of a solute. What is the final volume of this solution?
Savatey [412]

Answer: The final volume of this solution is 0.204 L.

Explanation:

Given: Molarity of solution = 2.2 M

Moles of solute = 0.45 mol

Molarity is the number of moles of solute present divided by volume in liters.

Molarity = \frac{no. of moles}{Volume (in L)}

Substitute the values into above formula as follows.

Molarity = \frac{no. of moles}{Volume (in L)}\\2.2 M = \frac{0.45}{Volume}\\Volume = 0.204 L

Thus, we can conclude that the final volume of this solution is 0.204 L.

7 0
3 years ago
What is the potential energy of the bowling ball as it sits on top of the building?
Tju [1.3M]

Answer:

Potential energy is energy due to an object's height above the ground.

Potential energy = mass x gravity x height

Kinetic energy is energy due to the motion of the object.

Kinetic energy = 1/2 x mass x velocity²

8 0
3 years ago
Who invented carbon element?
igor_vitrenko [27]
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8 0
3 years ago
A glucose solution that is prepared for a patient should have a concentration of 180 g/L. A nurse has 18 g of glucose. How many
Anuta_ua [19.1K]
You start by using proportions to find the number of liters of solution:

180 g of glucose / 1 liter of solution = 18 g of glucose / x liter of solution


=> x = 18 g of glucose * 1 liter of solution / 180 g of glucose = 0.1 liter of solution.


If you assume that the 18 grams of glucose does not apport volume to the solution but that the volume of the solution is the same volumen of water added (which is the best assumption you can do given that you do not know the how much the 18 g of glucose affect the volume of the solution) then you should add 0.1 liter of water.

Answer: 0.1 liter of water.

 
6 0
3 years ago
Read 2 more answers
A nuclear power plant operates at 40.0% efficiency with a continuous production of 1042 MW of usable power in 1.00 year and cons
Sergio039 [100]

Answer:

3.00 x 10^-11 joules / atom of U-235

Explanation:

We know that the formula for Power = Work done (w)/Time (t)

We need to get the joules from power , since Joules is the SI unit of work.

From the formula P = W/t

W = Power (P) * Time (t)

The SI unit for Time is seconds, hence we change 1 year in seconds

1yr * 365 days/yr * 24hrs/day * 60mins/hr * 60 secs/min = 31536000 secs

It was stated in the question that the plant operates at an efficiency of 40%,

Thus to get the true power we divide the power provided in the question by 0.4 or 40%

= X(0.4) = 1042MW

True Power X = 1042/0.4 = 2605MW

Thus true power = 2605 * 10^6 Watts

Now we have the time in seconds and true power in Watts, we then find the work done.

From our above formula P = W/t

W = P*t = (2605* 10^6) (31536000) =

Finally, we can solve for our energy (work):

P = W / T        PT = W = (2880x10^6) (31536000) = 8.22 x 10^16 joules

We then calculate the amount of energy released by only 1 single uranium-235 atom.

= 8.22 x 10^16 joules / 1.07x10^6 g U-235 (235 g / 1 mol)(1 mol/6.0210^23 atoms)

= 3.00 x 10^-11 joules / atom of U-235

5 0
3 years ago
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