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kiruha [24]
3 years ago
10

What type of chemical bond can form between an atom with 11 protons and an atom with 17 protons? what type of chemical bond can

form between an atom with 11 protons and an atom with 17 protons? non-polar covalent ionic hydrogen polar covalent?
Chemistry
2 answers:
asambeis [7]3 years ago
8 0
Ionic non polar is correct
Aloiza [94]3 years ago
5 0

atomic number of elements are the number of protons

in neutral atoms number of protons are equal to number of electrons

electrons are responsible for the chemical bonding in atoms

bonding depends on the number of valence electrons in the outermost shells.

atom A with 11 protons have 11 electrons, electronic configuration is - 2,8,1

atom B with 17 protons have 17 electrons, electron configuration is - 2,8,7

A has 1 valence electron and B has 7 valence electrons

therefore A prefers to give away its one valence electron and have a complete outer shell and B prefers to take in that one electron from A to become a complete octet.

The type of bond is an ionic bond formed by the transfer of electrons from one species to another species

answer is ionic



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Using the thermodynamic information in the ALEKS Data tab, calculate the standard reaction entropy of the following chemical rea
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ΔS° = - 47.2 J/mol.K

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5 0
3 years ago
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Question: Draw a valid Lewis structure for the molecule CH3NO in which there are no nonzero formal charges on any of the atoms.
iVinArrow [24]

The mentioned molecule with formula, CH₃NO where no bond is found between N and O can be depicted as formamide is shown in the attachment below.  

The formal charges = Number of valence electrons for the atom (V) - the number of electrons in lone pairs (N) - 1/2 (number of electrons in bond pairs, B)

FC = V - N - B/2

Thus, there is a need to calculate valence electrons, electrons in lone pairs, and the number of electrons in bond pairs for each atom in the mentioned molecule.  

V or valence electrons on C = 4e, on H = 1e, on N = 5e, and on O = 6e.  

N or electrons in lone pairs on C = 0e, on H = 0e, on N = 2e, and on O = 4e.  

B or number of electrons in bond pairs for C = 8e, for H = 2e, for N = 6e, and for O = 4e.  

Thus, the formal charges for each will be,  

C = 4 - 0 - (8/2) = 0

H = 1 - 0 - (2/2) = 0

N = 5 - 2 - (6/2) = 0

O = 6 - 4 - (4/2) = 0

Lewis dot structure for the given molecule is given in the attachment below:


3 0
3 years ago
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how do the properties of compounds compare to the properties of the elements from which they are composed
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<span>The elements that form the compound don't compare because it doesn't matter about the elements when they are combined. The elements that formed it together is completely different than the outcome compound. </span>
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