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andrew11 [14]
4 years ago
5

20%5C%5C%20%20%5C%3A%20or%20%5C%3A%20less%20%5C%3A%20than%20%5C%3A%20%20%20%5Csqrt%7B8%7D%20%20%2B%2015" id="TexFormula1" title=" \sqrt{11 + } \: 15 \: is \: greater \: than \\ \: or \: less \: than \: \sqrt{8} + 15" alt=" \sqrt{11 + } \: 15 \: is \: greater \: than \\ \: or \: less \: than \: \sqrt{8} + 15" align="absmiddle" class="latex-formula">
plz help
Mathematics
1 answer:
UkoKoshka [18]4 years ago
6 0
The square root of 11+15 is bigger
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I need help with thiss plz
Sedaia [141]

Answer:

Mia is right since the x-axis crosses the y-intercept and her line is an inequality.

Step-by-step explanation:

Hope this helps Kait:)

4 0
3 years ago
Read 2 more answers
Solve the System and write the solution as an ordered pair. <br><br> 3x+3y=6 <br> 5x-6y=15
Ugo [173]

\\ \sf\longmapsto 3x+3y=6\dots(1)

\\ \sf\longmapsto 5x-6y=15\dots(2)

Multiply eq(1) by 2 and eq(2) by 1

\\ \sf\longmapsto 6x+6y=12

\\ \sf\longmapsto 5x-6y=15

  • Add

\\ \sf\longmapsto 11x=27

\\ \sf\longmapsto x=\dfrac{27}{11}

Now

Put in eq(1)

\\ \sf\longmapsto 3\dfrac{27}{11}+3y=6

\\ \sf\longmapsto \dfrac{81}{11}+3y=6

\\ \sf\longmapsto 3y=6-\dfrac{81}{11}

\\ \sf\longmapsto 3y=\dfrac{66-81}{11}

\\ \sf\longmapsto 3y=\dfrac{15}{11}

\\ \sf\longmapsto y=\dfrac{15}{33}

4 0
3 years ago
Read 2 more answers
PLEASE SHOW WORK - HELP FAST
Ksivusya [100]

Answer:

SSS

∆PQR = 43

Step-by-step explanation:

The postulate to solve ∆PQR ≅ ∆STU is SSS. Both of the triangles have all three sides given, which means it can be solved for congruence.

9 + 6y + 5 + 14 = 9 + 8y +14

28 + 6y = 9 + 8y + 14

28 + 6y = 8y + 23

      -6y    -6y

--------------------------

  28 = 2y + 23

 -23           -23

---------------------

      5 = 2y

     ----   ----

      2      2  

  2.5  =   y

9 + 14 + 6(2.5) + 5

23 + 15 + 5

 23 + 20

     43

∆PQR = 43

4 0
3 years ago
Work out the length of ab, give your answer to 3 significant figures
Aleksandr [31]

Answer:

D = 9.85 units

Step-by-step explanation:

A (1,7) and B(10,3)

Using Distance Formula to find the length

=> Distance Formula = \sqrt{(x2-x1)^2+(y2-y1)^2}

=> D = \sqrt{(10-1)^2+(3-7)^2}

=> D = \sqrt{(9)^2+(-4)^2}

=> D = \sqrt{81+16}

=> D = \sqrt{97}

=> D = 9.85 units (Upto 3 sfs)

7 0
4 years ago
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Help me please I am so confused with this question!?!?!?!
BabaBlast [244]
The answer is 2, just follow the order of operations
4 0
3 years ago
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