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Burka [1]
3 years ago
7

how do you find the uncertainty of a single measurement? For example, I am trying to find the uncertainty of 26 grams. ​

Physics
1 answer:
worty [1.4K]3 years ago
6 0

Answer:

Please see answer below

Explanation:

The uncertainty will depend of the granularity of the instrument you use for the measurement.

For example, if you measure the length of a tabletop with a measuring tape with the smaller divisions given by the mm for example,then your measurement is limited by 1 mm (it cannot be better than that because your instrument doesn't have a finer division)

If you are using a digital scale to measure the weight of an object for example, and the scale displays in the readout 26.3 grams, then your uncertainty becomes 0.1 gram because that is the best your scale can read.

If on the other hand your scale reads no better than the gram, and gives you just 26 in the display, then the resolution of the scale is 1 gram, and that is what the uncertainty in your measurement is.

You have to report it as:  26 ± 1 g

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A person runs 400 meters in a straight line. What is their distance and displacement.
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hree identical resistors are connected in series. When a certain potential difference is applied across the combination, the tot
pav-90 [236]

Answer:

The power dissipated if the three resistors were connected in parallel across the same potential difference is 405 W

Explanation:

Given;

three identical resistors connected in series

let the first resistor = R₁

let the second resistor = R₂

let the third resistor = R₃

Rt = R₁ + R₂ + R₃

Since the resistors are identical, thus, R₁ = R₂ = R₃ = R

Rt = 3R

Power is given as;

P = IV = V² / R

P = \frac{V^2}{R_t} = \frac{V^2}{3R} \\\\3P = \frac{V^2}{R} ------equation(i)

If the 3 identical resistor connection were changed to parallel, then the equivalent resistance in the circuit will be;

\frac{1}{R_t} = \frac{1}{R_1} +\frac{1}{R_2} + \frac{1}{R_3} \\\\But, R_1 = R_2 = R_3\\\\\\frac{1}{R_t} = \frac{1}{R} +\frac{1}{R} + \frac{1}{R} \\\\\frac{1}{R_t} =\frac{3}{R} \\\\R_t = \frac{R}{3} \\\\P = \frac{V^2}{R_t} = \frac{3V^2}{R} \\\\P_{parallel} = \frac{3V^2}{R} ---------equation (ii)\\\\From \ equation \ (i), 3P_{series} = \frac{V^2}{R}, Substitute \ this \ into \ equation \ (ii)\\\\P = 3(\frac{V^2}{R} )\\\\P = 3(3P)\\\\P_{parallel} = 9P_{series}\\\\P_{parallel} = 9(45)\\\\

P_{parallel} = 405 \ W

Therefore, the power dissipated if the three resistors were connected in parallel across the same potential difference is 405 W

4 0
3 years ago
the amount of water returning to the earth through precipitation is blank the amount of water leaving the earth through evaporat
nalin [4]

<u>Answer:</u>

<em>The amount of water entering the earth through precipitation is equal to the amount of water leaving earth through transpiration.</em>

<u>Explanation:</u>

Rates of precipitation and evaporation vary widely according to regions and seasons. But in a global scale the rates are equal. Thus the total amount of earth’s water maintains its constancy even though there is a continuous change in forms of water.

Evaporation and transpiration are the forms in which Water leaves the earth and it returns to the earth in various forms of precipitation like rain, snow, dew, fog etc. This water then reaches ocean and land. The water that reaches the land flows as surface run off into rivers and water bodies or seep into the ground replenishing the ground water table.

5 0
3 years ago
A 2.30-kg cylindrical rod of length 2.00 m is suspended from a horizontal bar so it is free to swing about that end. a solid sph
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Solution:


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h = L(1 - cosΘ) → where here L is the distance to the CM 
0.03m = 1m(1 - cosΘ) = 1m - 1m*cosΘ 
Θ = arccos((1-0.29)/1) = 44.77 º 

8 0
3 years ago
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