Answer: 4.9 x 10^6 joules
Explanation:
Given that:
mass of boulder (m) = 2,500 kg
Height of ledge above canyon floor (h) = 200 m
Gravita-tional potential energy of the boulder (GPE) = ?
Since potential energy is the energy possessed by a body at rest, and it depends on the mass of the object (m), gravitational acceleration (g), and height (h).
GPE = mgh
GPE = 2500kg x 9.8m/s2 x 200m
GPE = 4900000J
Place result in standard form
GPE = 4.9 x 10^6J
Thus, the gravita-tional potential energy of the boulder-Earth system relative to the canyon floor is 4.9 x 10^6 joules
The blank distance is your answer
Answer:
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Explanation:
This is ur answer...
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The static frictional force is greater than the kinetic frictional force, so the static frictional force is greater than 1200 N.
<h2>Answer:</h2>
<u>Ball A has more kinetic energy</u>
<h2>Explanation:</h2>
As we know that Kinetic energy is given by
K. E = 1/2 mv²
Since K E is dependent upon both mass and velocity so increasing mass will produce more kinetic energy if the speed remains constant
As the mass of ball A is greater than ball B so we can say that the kinetic energy of ball is more than ball B