The temperature of the air in the open orang pipe has been altered by 18.73° C
The frequency of an open orang pipe is estimated by using the formula:

Then, the combination of the frequency of the tuning fork and the open orang pipe is:

These combinations of frequency produce 4 beats per sound.
i.e.



When it is altered, the beats first diminish and increase again by 4.
i.e.


If we equate both equations (1) and (2) together, we have:

However, from our previous knowledge, we understand that the velocity of an object varies directly proportional to the square root of its temperature.
Hence;
- when the temperature of the pipe = unknown ???
- the temperature of the open orang pipe = 15
∴

By squaring both sides, we have:




T = 306.726912 - 273
T ≅ 33.73 ° C
∴
The change in temperature ΔT = 33.73° C - 15° C
The change in temperature ΔT = 18.73° C
Learn more about wave frequency here:
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<h3>Answer</h3>
m/s^2 (meter per sec square)
Explanation:
acc = change in velocity/time
= distance/time
----------------
time
= m/s
------
s
=m/s^2
Answer:
I would say since it is still water the stream flow is 0km/h. Especially because he needs the same time upstream as He does down stream.
Answer:
The energy lost by the atoms is given off as an electromagnetic wave. ... even if it's not very intense, will always cause electrons to be emitted.
Explanation:
Let, the temperature of Sun's surface = c
So, 5c = 30, 000
c = 30,000 / 5
c = 6,000
In short, Your Answer would be 6000
Hope this helps!