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sukhopar [10]
3 years ago
12

A 5 mole sample of liquid acetone is converted to a gas at 75.0°C. If 628 J are required to raise the temperature of the liquid

to the boiling point, 15.600 kJ are required to evaporate the liquid, and 712 J are required to raise the final temperature to 75.0°C, what is the total energy required for the conversion?
Chemistry
1 answer:
velikii [3]3 years ago
7 0
The total energy required for this conversion is equivalent to the sum of the energies that are used. There are three steps:

1) Heating of liquid acetone
This used 628 J

2) Evaporation of acetone
This used 15.6 kJ or 15,600 J

3) Heating of acetone vapors
This used 712 J

Adding these quantities,

Total energy = 628 + 15,600 + 712

The total energy required was <span>16940 Joules of 16.94 kJ</span>
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Gold is alloyed with other metals to increase its hardness in making jewelery.a) Consider a piece of gold jewelry the weighs 9.8
irinina [24]

Answer:

A). Percentage of gold by mass of the jewellery =

(6.059÷9.85) × 100 = 61.5%

B). Purity of the gold = 0.615 × 24 = 14.76 karat ~ 15 karat gold

Explanation:

Mass of jewellery = 9.85g Volume of jewellery = 0.675cm^3.

Density of gold = 19.3g/cm^3 and density of silver = 10.5g/cm^3

Let the volume of gold in the jewellery be X and the volume of silver in the jewellery be Y

Hence we have

Density = mass/volume or mass = volume × density = for gold = X × 19.3g/cm^3 and for the silver = Y × 10.5g/cm^3

19.3X +10.5Y = 9.85g

Also volume of jewellery is given by

Volume of silver in the jewellery + volume of gold in the jewellery = 0.675cm^3.

X + Y = 0.675cm^3.

Solving the above equations we have

Y = 0.675 - X

Which gives

19.3X + 10.5Y = 9.85g

19.3X + 10.5 × (0.675 - X) =9.85g

19.3X + 7.0875 - 10.5X = 9.85

8.8X + 7.0875 = 9.85

8.8X = 2.7625

or X = 0.3139 cm^3

But Y = 0.675 - X

Hence Y = 0.675 - 0.3139 = 0.3611 cm^3

Mass of gold in the jewellery = volume of gold × Density of gold = 0.3139 × 19.3 = 6.059 g

Also mass of silver = 10.5 × 0.3611 = 3.7913g

A). Percentage of gold by mass of the jewellery =

(6.059÷9.85) × 100 = 61.5%

B). Purity of the gold = 0.615 × 24 = 14.76 karat ~ 15 karat gold

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How many atoms are there in 2.43 g of calcium?
Evgen [1.6K]

Answer:

Explanation:

We're asked to calculate the number of atoms of

Ca

in

153

g Ca

.

What we must first do is convert the given mass of calcium to moles of calcium, using its molar mass (referring to a periodic table, this is

40.08

g

mol

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153

g Ca

(

1

mol Ca

40.08

g Ca

)

=

3.82

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Using Avogadro's number,

6.022

×

10

23

particles

mol

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3.82

mol Ca

(

6.022

×

10

23

atoms Ca

1

mol Ca

)

=

2.30

×

10

24

atoms Ca

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