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sleet_krkn [62]
3 years ago
7

A sample of ammonia gas, NH3, has a volume of 285.0 mL at a pressure of 98.50 kPa. What will the volume of the ammonia be at a p

ressure of 94.20 kPa? Assume that all other properties of the gas remain constant.
Chemistry
2 answers:
enyata [817]3 years ago
6 0
<span>We know that an ideal gas keeps the relation between pressure, volume and temperature constant.
    P * V / T = constant
   Then if we have the gas in two diferente state:
   P1*V1/T1 = P2*V2/T2
    Temperature remain constant so then:
   P1*V1 = P2*V2
  98.5*285 = 94.2*V2
  V2 = 98.5*285/94.2 = 298 ml
   So the volume of the ammonia will be 298 ml</span>
choli [55]3 years ago
6 0
Using Avogadro's law 

<span>where: P1V1/n1T1 = P2V2/n2T2 </span>

<span>The problem states it implicitly but n and T are constant </span>

<span>P1V1 = P2V2 </span>

<span>V2 = P1V1/P2 </span>

<span>P1 = 98.50 kPa </span>
<span>V1 = 285.0 mL </span>
<span>P2 = 94.20 kPa </span>

<span>V2 = (98.50 x 285)/94.20 </span>
<span>V2 = 298.00 mL </span>

<span>The volume increases to 298 mL.</span>
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