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enot [183]
3 years ago
5

You perform an experiment using two bean seeds planted in identical soil. one seed is kept in a window, where it receives a lot

of light. The other seed is kept in a cupboard and received no light. the seed that gets a lot of light grows very tall and has bright green leaves. The other seed is short and has yellow leaves. What conclusion do you draw?
a) The seeds grew differently because of many different environmental conditions
b) The seeds grew differently because of the different environmental conditions and the amount of air they received
c) The seeds grew differently because of the different environmental conditions and the amount of light they received
d) The seeds had different genes for height and color, making one tall and green and the other short and yellow
Chemistry
1 answer:
My name is Ann [436]3 years ago
7 0

Answer: A

Explanation: because I am your father

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One way of obtaining pure sodium carbonate is through the decomposition of the mineral trona, Na3(CO3)(HCO3)·2H2O. 2Na3(CO3)(HCO
zhenek [66]
Percentage yield = (actual yield / theoretical yield) x 100%

The balanced equation for the decomposition is,
 2Na₃(CO₃)(HCO₃)·2H₂O(s) → 3Na₂CO₃(s) + CO₂(g) + 5H₂<span>O(g)

The stoichiometric ratio between </span>Na₃(CO₃)(HCO₃)·2H₂O(s)  and Na₂CO₃(s) is 2 : 3

The decomposed mass of Na₃(CO₃)(HCO₃)·2H₂O(s) = 1000 kg
                                                                                     = 1000 x 10³ g

Molar mass of Na₃(CO₃)(HCO₃)·2H₂O(s) = 226 g mol⁻¹
moles of Na₃(CO₃)(HCO₃)·2H₂O(s) = mass / molar mass
                                                         = 1000 x 10³ g / 226 g mol⁻¹
                                                         = 4424.78 mol

Hence, moles of Na₂CO₃ formed = 4424.78 mol x \frac{3}{2}
                                                     = 6637.17 mol

Molar mass of Na₂CO₃ = 106 g mol⁻¹

Hence, mass of Na₂CO₃ = 6637.17 mol x 106 g mol⁻¹
                                        = 703540.02 g
                                        = 703.540 kg

Hence, the theoretical yield of Na₂CO₃ =  703.540 kg
Actual yield of Na₂CO₃ = 650 kg

Percentage yield = (650 kg / 703.540 kg) x 100%
                            = 92.34%
7 0
3 years ago
Fill in the left side of this equilibrium constant equation for the reaction of benzoic acid (HC_6H_5CO_2) with water.
il63 [147K]

Answer:

[C₆H₅COO⁻][H₃O⁺]/[C₆H₅COOH] = Ka

Explanation:

The reaction of dissociation of the benzoic acid in water is given by the following equation:

C₆H₅-COOH + H₂O  ⇄  C₆H₅-COO⁻  +  H₃O⁺    (1)

The dissociation constant of an acid is the measure of the strength of an acid:

HA ⇄ A⁻ + H⁺        (2)

K_{a} = \frac{[A^{-}][H^{+}]}{[HA]}      (3)

<em>Where the dissociation constant of the acid (Ka) is equal to the ratio of the concentration of the dissociated forms of the acid, [A⁻][H⁺], and the concentration of the acid, [HA].     </em>

So, starting from the equations (2) and (3), the constant equation for the dissociation reaction of benzoic acid in water, of the equation (1), is:

K_{a} = \frac{[C_{6}H_{5}COO^{-}][H_{3}O^{+}]}{[C_{6}H_{5}COOH]}

I hope it helps you!          

6 0
2 years ago
Enter a range of values for x, 2x+10, 14 ​
PIT_PIT [208]

Answer:

62 degrees and 15.

Explanation:

3 0
3 years ago
Draw the structure of 1,4-hexanediamine.
brilliants [131]

Answer:

1,4-hexanediamine contains two -NH_{2} functional groups.

Explanation:

1,4-hexanediamine is an organic molecule which contains two -NH_{2} functional groups at C-1 and C-4 position.

The longest carbon chain in 1,4-hexanediamine contains six carbon atoms.

Molecular formula of 1,4-hexanediamine is C_{6}H_{16}N_{2}.

1,4-hexanediamine used as a bidentate ligand in organometallic chemistry.

The structure of 1,4-hexanediamine is shown below.

5 0
3 years ago
IF CORRECT YOU WILL GET BRAINLIEST
Scorpion4ik [409]

Answer:

C 5 mol A; 6 mol B

Explanation:

eto po answer ko sana makatulong

3 0
2 years ago
Read 2 more answers
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