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Vladimir [108]
3 years ago
9

What is the number of electrons that move past a point in a wire carrying 500 A of current in 4.0 minutes

Physics
1 answer:
mr Goodwill [35]3 years ago
3 0
The current is defined as the amount of charge Q that passes through a given point of a wire in a time \Delta t:
I= \frac{Q}{\Delta t}
Since I=500 A and the time interval is
\Delta t=4.0 min=240 s
the charge is
Q=I \Delta t=(500 A)(240 s)=1.2 \cdot 10^5 C

One electron has a charge of q=1.6 \cdot 10^{-19}C, therefore the number of electrons that pass a point in the wire during 4 minutes is
N= \frac{Q}{q}= \frac{1.2 \cdot 10^5 C}{1.6 \cdot 10^{-19}C}=7.5 \cdot 10^{23} electrons
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Answer:

21.53 x 10^{6} N

Explanation:

force (F) = 4.71 x 10^{3} N

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how much work is done.

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What is the speed of a 48-kilogram dog running across<br>a lawn with 216 joules of kinetic energy?​
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Answer:

3m/s

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/sqrt{v^2} = /sqrt{9m^2/s^2}

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1 hectopascal (hPa) is equivalent to 100 Pa
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A thin rod of length 0.75 m and mass 0.42 kg is suspended freely from one end. It is pulled to one side and then allowed to swin
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Answer:

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(B) 0.15 m

Explanation:

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h is the horizontal distance between the center of mass and the rotational axis of the rod

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I = 0.07875 kg.m^{2}

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   Ki + Ui = Kf + Uf

   at the maximum height velocity = 0 therefore final kinetic energy = 0

   Ki + Ui = Uf

   Ki = Uf - Ui

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where (H-h) = rise in the center of mass

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