Answer:
21.53 x 10^{6} N
Explanation:
force (F) = 4.71 x 10^{3} N
distance (s) = 4.57 km = 4570 m
how much work is done.
work = force x distance
work = 4.71 x 10^{3} x 4570 = 21.53 x 10^{6} N
Answer:
3m/s
Explanation:
K.E= (1/2)mv^2
216j= (1/2)48kg • v^2
216J=24kg•v^2
v^2 = (216J)/(24kg)
v^2= 9m^2/s^2
/sqrt{v^2} = /sqrt{9m^2/s^2}
V =3m/s
1 hectopascal (hPa) is equivalent to 100 Pa
Answer:
(A) 0.63 J
(B) 0.15 m
Explanation:
length (L) = 0.75 m
mass (m) =0.42 kg
angular speed (ω) = 4 rad/s
To solve the questions (a) and (b) we first need to calculate the rotational inertia of the rod (I)
I = Ic + m
Ic is the rotational inertia of the rod about an axis passing trough its centre of mass and parallel to the rotational axis
h is the horizontal distance between the center of mass and the rotational axis of the rod
I =
)^{2}[/tex]
I =
)^{2}[/tex])
I = 0.07875 kg.m^{2}
(A) rods kinetic energy = 0.5I
= 0.5 x 0.07875 x
= 0.63 J 0.15 m
(B) from the conservation of energy
initial kinetic energy + initial potential energy = final kinetic energy + final potential energy
Ki + Ui = Kf + Uf
at the maximum height velocity = 0 therefore final kinetic energy = 0
Ki + Ui = Uf
Ki = Uf - Ui
Ki = mg(H-h)
where (H-h) = rise in the center of mass
0.63 = 0.42 x 9.8 x (H-h)
(H-h) = 0.15 m
In phase would mean both waves are at a positive peak, out of phase would mean one is at a positive whilst the other is at a negative. Out of phase would mean the waves cancel each other out