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3 years ago

What is the percentage by mass of nitrogen in the fertiliser (NH4)3PO4? [Ar: H = 1, N = 14, O = 16, P = 31]

Chemistry

1 answer:

BaLLatris [955]3 years ago

6 0

Answer:

(NH4)3PO4 is 28.2 % N , 8.1% H, 20.8 % P and 43.0 % O by mass.

Explanation:

the formula In chemistry, the mass fraction of a substance within a mixture is the ratio w_{i} of the mass m_{i} of that substance to the total mass {\displaystyle m_{\text{tot}}} of the mixture. Expressed as a formula, the mass fraction is: {\displaystyle w_{i}={\frac {m_{i}}{m_{\text{tot}}}}.}

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3 years ago

Which term is the force per unit area or collisions with the walls of the container?

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3 years ago

A solution is made by dissolving 3.14 g of NaCl in 79.9 mL of water. What is the concentration of sodium chloride in units of we

Trava [24]

The concentration of sodium chloride in units of weight/volume percent is 3.93g/ml

Given that

3.93 (w/v) NaCl

Weight NaCl = 3.14g

Volume of water = 79.9mL

W/V is usually represented in g/mL, so no need to change anything

3.14g/79.9mL *100 = 3.93 g/mL (%)

One mole of NaCl contains 6.022 x 10 23 NaCl formula units.

• Use the mole quantity to count formulas by weighing them.

• Mass of a mole of particles = mass of 1 particle x 6.022 x 1023

• The mass of an atom in amu is numerically the same

as the mass of one mole of atoms of the element in grams.

• One atom of sulfur has a mass of 32.07 amu;

one mole of S atoms has a mass of 32.07 g.

Mass of 1 H atom: 1.008 amu x 1.661 x10-24 g/amu = 1.674 x10-24 g

Mass of 1 mole of H atoms:

1.674 x10-24g/H atom x 6.022 x1023H atoms = 1.008 g

Learn more about Weight / volume Percentage here

brainly.com/question/14296094

#SPJ4

6 0

1 year ago

A una mezcla de 300g, formada con 60% P/P de Hierro y 40% P/P de Arena, se le adicionan 135g de Cobre y 2,77g de Aluminio. ¿Cuál

Svetllana [295]

Answer:

$\%P/P_{hierro}=41.1\%\\\\\%P/P_{arena}=24.4\%\\\\\%P/P_{cobre}=30.8\%\\\\\%P/P_{aluminio}=0.6\%$

Explanation:

¡Hola!

En este caso, dado que estamos tratando con problem sobre porcentaje peso/peso de hierro, arena, cobre y aluminio, primero debemos calcular la masa inicial de estos dos primeros en la mezcla original de acuerdo con:

$m_{hierro}=300g*0.60=180g\\\\m_{arena}=300*0.40=120g$

Ahora si podemos calcular la masa de la mezcla final como la suma de las masas de todos los constituyentes de la mezcla:

$m_T=180g+120g+135g+2.77g=437.77g$

Finalmente, podemos calcular los porcentajes P/P como se muestra a continuación:

$\%P/P_{hierro}=\frac{180g}{437.77g} *100\%=41.1\%\\\\\%P/P_{arena}=\frac{120g}{437.77g} *100\%=24.4\%\\\\\%P/P_{cobre}=\frac{135g}{437.77g} *100\%=30.8\%\\\\\%P/P_{aluminio}=\frac{g}{437.77g} *100\%=0.6\%$

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2 years ago

How many atoms of Oxygen (O) are there in the products of the following equation:

jasenka [17]

Answer:

We can say, there are 4 mol of oxygen with (4 . NA) = 2.40ₓ10²⁴ atoms

Or just, 4 atoms oxygen.

Explanation:

CH₄ + 2O₂ → CO₂ + 2H₂O

1 mol of methane reacts with 2 mol of oxygen to produce 1 mol of carbon dioxide and 2 mol of water.

We count in 1 mol of CO₂, we have 2 mol of oxygen

In 2 mol of water, we have 2 mol of oxygen.

We can say, there are 4 mol of oxygen with (4 . NA) = 2.40ₓ10²⁴ atoms

Or just, 4 atoms oxygen.

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3 years ago