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Digiron [165]
3 years ago
10

Which expression shows the simplified form of (8 r Superscript negative 5 Baseline) Superscript negative 3? 8 r Superscript 15 S

tartFraction 8 Over r Superscript 15 Baseline EndFraction 512 r Superscript 15 StartFraction r Superscript 15 Baseline Over 512 EndFraction
Mathematics
2 answers:
givi [52]3 years ago
7 0

Answer:

free pointzzz

Step-by-step explanation:

Delvig [45]3 years ago
3 0

Answer:

\frac{r^{15}}{512}

Step-by-step explanation:

Given

(8r^{-5})^{-3}

Required

Simplify

This can be simplified using the following law of indices;

(ab)^n = a^{n}b^{n}

The equation becomes

(8^{-3})(r^{-5})^{-3}

Express 8^{-3} as a fraction

(\frac{1}{8^{3}})(r^{-5})^{-3}

Simplify 8^3

(\frac{1}{8*8*8})(r^{-5})^{-3}

(\frac{1}{512})(r^{-5})^{-3}

The expression can further be simplified using the following law of indices;

(a^m)^n = a^{mn}

(\frac{1}{512})(r^{-5})^{-3} becomes

(\frac{1}{512})(r^{-5*-3})

(\frac{1}{512})(r^{15})

\frac{r^{15}}{512}

<em>Hence, the solution to </em>(8r^{-5})^{-3}<em> is </em>\frac{r^{15}}{512}<em></em>

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